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BARSIC [14]
3 years ago
15

Use the Pythagorean theorem to obtain the function​ D(x) for the length of the diagonal of a double square of width x.

Mathematics
1 answer:
Yuri [45]3 years ago
4 0

Answer:

D(x)= x\sqrt{2}

Step-by-step explanation:

Given

Side = x

Required

Represent the diagonal as a function

Using Pythagoras theorem, the diagonal is:

D^2= Side^2 + Side^2

Substitute x for Side

D^2= x^2 + x^2

D^2= 2x^2

Take the square root of both sides

D= \sqrt{2x^2

Split

D= \sqrt{2} * \sqrt{x^2

D= \sqrt{2} * x

D= x\sqrt{2}

Express as a function.

D(x)= x\sqrt{2}

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Answer:

B

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Answer:

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Step-by-step explanation:

We know that the perimeter of a rectangle = 2(l+w)

i.e.

P = 2(l+w)

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Answer:

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Step-by-step explanation:

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Now plug in the given functions in the above formula, we get

= (x^5 - x^4 + x^2) / -x^2

We can factorize the numerator.

In x^5 - x^4 + x^2. the common factor is x^2, so we can take it out and write the remaining terms in the parenthesis.

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Now we gave x^2 both in the numerator and in the denominator, we can cancel it out.

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When we dividing the numerator by -1, we get

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Answer: c) -x^3 + x^2 - 1

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Thank you.

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