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3 years ago

3

Mathematics

1 answer:

adoni [48]3 years ago

8 0

Answer:

The solution set is (5,6).

Step-by-step explanation:

Given equations are:

-6x + 6y= 6 Eqn 1

-6x + 3y=-12 Eqn 2

Subtracting Eqn 2 from Eqn 1

(-6x+6y)-(-6x+3y)= 6-(-12)

-6x+6y+6x-3y=6+12

3y = 18

Dividing both sides by 3

$\frac{3y}{3}=\frac{18}{3}\\y=6$

Putting y=6 in Eqn 1

-6x+6(6)=6

-6x+36=6

-6x=6-36

-6x=-30

$\frac{-6x}{-6}=\frac{-30}{-6}\\x=5$

Hence,

The solution set is (5,6).

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Find the factors and the greatest common factor 375,66,333

lyudmila [28]

Answer:

the greatest common factor is 3

Step-by-step explanation:

375: 1, 3, 5,11, 15, 25, 75, 125, 375

66: 1, 2, 3, 6, 11, 22, 33, 66

333: 1, 3, 9, 37, 111, 333

5 0

3 years ago

The weight, w, of a spring in pounds is given by 0.9 times the square root of the energy, E, stored by the spring in joules. If

frutty [35]

For this case we have the following equation:
$w = 0.9* \sqrt{E}$
Where,
w: The weight of a spring in pounds
E: the energy stored by the spring in joules.
Substituting values we have:
$w = 0.9* \sqrt{12}$
Making the corresponding calculation:
$w=3.12$
Answer:
the approximate weight of the spring in pounds is:
$w=3.12$

4 0

3 years ago

Read 2 more answers

Hi can anyone help me? :)

mixas84 [53]

Answer:

$d(n) = - ( {7}^{n - 1} )$

8 0

3 years ago

Please help with 6 and 7

Maru [420]

Answer:

6a) i- 2hrs 36mins ii- 3hrs 12mins

b) car A≈ 76.9km/h car B≈ 62.5km/h

c)------

7a) 35km

b) car A=75km car B=60km

c) 30km

d) car A≈36mins car B≈48mins

Step-by-step explanation:

6a) Using the graph follow the lines until they finish then go downwards until you get to the x-axis. The x-axis is going up by 12mins for each square.

b) Using the answer from a, you divide 200km by the time.

For car A 2hrs 36mins becomes 2.6 because 36mins/60mins=0.6

∴ car A: 200/2.6≈ 76.92km/h

For car B 3hrs 12mins becomes 3.2 because 12mins/60mins=0.2

∴ car B: 200/3.2≈ 62.5km/h

7a) Using the graph go down from where the line of car A finished to meet car B. The y-axis is going up by 5km for each square.

b) Starting from the x-axis at 1 hour go upwards to see where you meet the car B line (60km) and car A line(75km). (sorry if that does not really make sense).

c) Difference from car A line to car B:

155km-125km=30km

d) Going across from 50km meet car A line and go down to see it has been travelling for approx. 36mins. Then continue across to car B line, go down to see it reached 50km at approx. 48mins.

Hope this helps.

5 0

3 years ago

If 4321 - 4322 = 10 <br> Then what's 3321 - 3322 = ?

ArbitrLikvidat [17]

Answer:

10 sorry if i'm wrong

Step-by-step explanation:

8 0

3 years ago