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Anna71 [15]
3 years ago
10

At a particular fast food restaurant, tacos cost $1.29 and

Mathematics
1 answer:
Arlecino [84]3 years ago
4 0

Answer:

Michael bought 18 tacos and 9 burritos.

Step-by-step explanation:

Since at a particular fast food restaurant, tacos cost $ 1.29 and burritos cost $ 2.19, and Michael spent a total of $ 42.93 at the restaurant to buy food for a party, if he purchased half as many burritos as tacos, to determine how many tacos did he buy, the following calculation must be performed:

1.29 x 20 + 2.19 x 10 = 47.7

1.29 x 16 + 2.19 x 8 = 38.16

1.29 x 18 + 2.19 x 9 = 42.93

So Michael bought 18 tacos and 9 burritos.

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Answer:

Answers are below

Step-by-step explanation:

Hour 0                 1 bacterium

Hour 1                  3 bacterium

Hour 2                 9 bacterium

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Hour 5            243 bacterium

Hour 6            729 bacterium

After 24 hours, the number of the bacterium will reach 282,429,536,481.

B)  This table represents exponential growth because of the number of bacterium always being multiplied by 3.

C)  The reason that any number to the zero power is one is that any number to the zero power is just the product of no numbers at all, which is the multiplicative identity, 1.

D)  Y = 1 + 3 to the power of x

E)  The rule would change by having all of the numbers multiplied by 100 since there is 100 bacterium at Hour 0.

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3 years ago
1. Round this number to the nearest hundred.
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Answer:

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Step-by-step explanation:

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When you round 579, the hundredths place is a 9, which is over 5 so you add 1 to seven to get 8.

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Consider the differential equation x2y′′ − 9xy′ + 24y = 0; x4, x6, (0, [infinity]). Verify that the given functions form a funda
pantera1 [17]

Answer:

The functions satisfy the differential equation and linearly independent since W(x)≠0

Therefore the general solution is

y= c_1x^4+c_2x^6

Step-by-step explanation:

Given equation is

x^2y'' - 9xy+24y=0

This Euler Cauchy type differential equation.

So, we can let

y=x^m

Differentiate with respect to x

y'= mx^{m-1}

Again differentiate with respect to x

y''= m(m-1)x^{m-2}

Putting the value of y, y' and y'' in the differential equation

x^2m(m-1) x^{m-2} - 9 x m x^{m-1}+24x^m=0

\Rightarrow m(m-1)x^m-9mx^m+24x^m=0

\Rightarrow m^2-m-9m+24=0

⇒m²-10m +24=0

⇒m²-6m -4m+24=0

⇒m(m-6)-4(m-6)=0

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Therefore the auxiliary equation has two distinct and unequal root.

The general solution of this equation is

y_1(x)=x^4

and

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First we compute the Wronskian

W(x)= \left|\begin{array}{cc}y_1(x)&y_2(x)\\y'_1(x)&y'_2(x)\end{array}\right|

         = \left|\begin{array}{cc}x^4&x^6\\4x^3&6x^5\end{array}\right|

         =x⁴×6x⁵- x⁶×4x³    

        =6x⁹-4x⁹

        =2x⁹

       ≠0

The functions satisfy the differential equation and linearly independent since W(x)≠0

Therefore the general solution is

y= c_1x^4+c_2x^6

5 0
3 years ago
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