3 years ago

Which direction does the graph of the equation shown below open? right, left, up, or down? x^2+6x-4y+5=0

1 answer:

7 0

X^2 + 6x - 4y + 5 = 0
4y = x^2 + 6x + 5
y = 1/4x^2 + 3/2x + 5/4

Since, x is the squred part and x^2 has a positive coefficient, therefore, the graph opens up.

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Please answer!

eduard

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Step-by-step explanation:

$(-2x^3+x-5)(x^3-3x-4)\\ \\ =(-2x^3 \times x^3)+(-2x^3 \times-3x)+(-2x^3 \times -4)+(x \times x^3)+(x \times -3x)+(x \times -4)+(-5 \times x^3)+(-5 \times -3x)+(-5 \times -4)\\
\\
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\\
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