Find the distance and midpoint between (3,6) and (5,11)
1 answer:
You might be interested in
Answer:
a) the area of a square is in terms of x is
centimeter square
b)The length of the rectangle is l = (x+1)
l = 7+1 =8 cm
The width of the rectangle is w = [(x+1)-5]
w = (7+1)-5 =3 cm
Step-by-step explanation:
a) the area of a square is in terms of x is
area of square is
=
b) Given length is l = (x+1) cm and
the width is 5 cm less than its length.
so we have take width is w = (x+1)-5 cm
Given area of triangle is 24 cm
Area of rectangle = length X width
24 = (x+1)(x+1 -5 )
now simplification
apply (a+b)^2 = a^2+2 a b+b^2
now find factors of 28 = 7 X 4 is
x = -4 and x=7
there fore you have to choose x = 7
The length of the rectangle is l = (x+1)
l = 7+1 =8
The width of the rectangle is w = [(x+1)-5]
w = (7+1)-5 = 3
<u>Verification:-</u>
Given area of rectangle = 24 = 8 X 3
24 =24
so we can not choose x=-4
we have to choose x =7 only