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Marta_Voda [28]
3 years ago
9

A bike rental shop charges $8 per hour and $4 insurance. How many hours can I rent the bike for if I have $20.

Mathematics
2 answers:
hjlf3 years ago
6 0
Answer :
Two Hours

Step By Step :
20-4=16
16/8=2
8090 [49]3 years ago
3 0

Answer:

2 hours

Step-by-step explanation:

Subtract the 4 already then divide 16 by 8 and you get 2 :)

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4x+6+ 3=-8<br> 2<br> What is x? <br> 4x+6 &lt;&lt;&lt;&lt;<br> 2 &lt;&lt;&lt; It’s a fraction
Andreas93 [3]

Answer:

-17/4

Step-by-step explanation:

4x+6+3=-8

4x+9=-8

-9 -9

4x=-17

÷4 ÷4

X=-17⁄4

6 0
3 years ago
Please help!?<br><br> Evaluate the expression 5V - 6w when v= 4 and w= 2.
Rudik [331]

Answer:

8

Step-by-step explanation:

5V-6W

V=4.    W=2.  

5(4)-6(2)

20-6(2)

20-12=

8

8 0
3 years ago
Find the midpoint of the segment below and enter its coordinates as an ordered pair. If necessary, express the coordinates as fr
Vladimir [108]
The correct answer is (5/2, -7/2)
3 0
3 years ago
What's -18÷(1-4+-2-4) explain pls need help​
Mrac [35]

Answer:

the answer is 2.

Step-by-step explanation:

i dont know how to explain sorry

4 0
3 years ago
In a survey, the planning value for the population proportion is p* = 0.35. How large a sample should be taken to provide a 95%
lions [1.4K]

Answer:

n=\frac{0.35(1-0.35)}{(\frac{0.05}{1.96})^2}=349.59  

And rounded up we have that n=350  

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

p represent the real population proportion of interest

\aht p represent the estimated proportion for the sample

n is the sample size required (variable of interest)

z represent the critical value for the margin of error

Solution to the problem

The population proportion have the following distribution  

p \sim N(p,\sqrt{\frac{\hat p(1-\hat p)}{n}})  

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 95% of confidence, our significance level would be given by \alpha=1-0.95=0.05 and \alpha/2 =0.025. And the critical value would be given by:  

z_{\alpha/2}=-1.96, z_{1-\alpha/2}=1.96  

The margin of error for the proportion interval is given by this formula:  

ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}} (a)  

And on this case we have that ME =\pm 0.05 and we are interested in order to find the value of n, if we solve n from equation (a) we got:  

n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2} (b)

And replacing into equation (b) the values from part a we got:  

n=\frac{0.35(1-0.35)}{(\frac{0.05}{1.96})^2}=349.59  

And rounded up we have that n=350  

6 0
3 years ago
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