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3 years ago

Prove that (1+sin2x)/(1-sin2x)=cot^2(x-pi/4)

Mathematics

1 answer:

Jlenok [28]3 years ago

4 0

Answer:

it's simple

Step-by-step explanation:

refer the image

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Please help with this ny teacher wants to ask me how to do it next

nataly862011 [7]

Answer:

x= -7

Step-by-step explanation:

1/2(4-6x)=23

Take1/2 of the numbers in the (). It will be 2-3x.

2-3x=23 subtract 2 from both sides to get x by itself

-3x=21 now divide the 21 by -3

x= -7

6 0

3 years ago

Read 2 more answers

Solve for v. M=bv/k Please help!!! I'm horrible at math.

Semenov [28]

First, I like switching the sides so that the equation looks like this: bv/k=M
Then get bv alone by multiplying both sides by k: bv=kM
After that, divide both sides by b to get v by itself: v=kM/b
I hope this helps you!

7 0

3 years ago

Assume z = x + iy, then find a complex number z satisfying the given equation. d. 2z8 – 2z4 + 1 = 0

kodGreya [7K]

Answer: complex equations has n number of solutions, been n the equation degree. In this case:

$Z=\frac{\sqrt[8]{2} }{\sqrt[4]{2}} e^{i11,25°}$

$Z=\frac{\sqrt[8]{2} }{\sqrt[4]{2}} e^{i101,25°}$

$Z=\frac{\sqrt[8]{2} }{\sqrt[4]{2}} e^{i191,25°}$

$Z=\frac{\sqrt[8]{2} }{\sqrt[4]{2}} e^{i281,25°}$

$Z=\frac{\sqrt[8]{2} }{\sqrt[4]{2}} e^{i78,75°}$

$Z=\frac{\sqrt[8]{2} }{\sqrt[4]{2}} e^{i168,75°}$

$Z=\frac{\sqrt[8]{2} }{\sqrt[4]{2}} e^{i258,75°}$

$Z=\frac{\sqrt[8]{2} }{\sqrt[4]{2}} e^{i348,75°}$

Step-by-step explanation:

I start with a variable substitution:

$Z^{4} = X$

Then:

$2X^{2}-2X+1=0$

Solving the quadratic equation:

$X_{1} =\frac{2+\sqrt{4-4*2*1} }{2*2} \\X_{2} =\frac{2-\sqrt{4-4*2*1} }{2*2}$

$X=\left \{ {{0,5+0,5i} \atop {0,5-0,5i}} \right.$

Replacing for the original variable:

$Z=\sqrt[4]{0,5+0,5i}$

or $Z=\sqrt[4]{0,5-0,5i}$

Remembering that complex numbers can be written as:

$Z=a+ib=|Z|e^{ic}$

Using this:

$Z=\left \{ {{{\frac{\sqrt{2}}{2} e^{i45°} } \atop {{\frac{\sqrt{2}}{2} e^{i-45°} }} \right.$

Solving for the modulus and the angle:

$Z=\left \{ {{\sqrt[4]{\frac{\sqrt{2}}{2} e^{i45}} = \sqrt[4]{\frac{\sqrt{2}}{2} } \sqrt[4]{e^{i45}} } \atop {\sqrt[4]{\frac{\sqrt{2}}{2} e^{i-45}} = \sqrt[4]{\frac{\sqrt{2}}{2} } \sqrt[4]{e^{i-45}} }} \right.$

The possible angle respond to:

$RAng_{12...n} =\frac{Ang +360*(i-1)}{n}$

Been "RAng" the resultant angle, "Ang" the original angle, "n" the degree of the root and "i" a value between 1 and "n"

In this case n=4 with 2 different angles: Ang = 45º and Ang = 315º

Obtaining 8 different angles, therefore 8 different solutions.

3 0

3 years ago

HELP A BROTHAAA OUTT

tekilochka [14]

B) p=9t

he gets paid $9/hr, and his pay depends how many hours he works.

5 0

3 years ago

Find the measure of angle 1 and 2 pls

Flura [38]

Answer:

Your answer is

1. 42.5

2. 95

Hope that this is helpful. Vote and like it

4 0

3 years ago