Answer:
y = 1, x = - 8
or
(-8, 1)
Step-by-step explanation:
-x + 4y = 12
x + y = -7
add the equations together
0x + 5y = 5
5y = 5
y = 1
substitute y for 1 in one of the original equations to find x
x + y = -7
x + 1 = -7
x + 1 - 1 = - 7 - 1
x = - 7 - 1
x = -8
Answer:
5
Step-by-step explanation:
Complete question:
The growth of a city is described by the population function p(t) = P0e^kt where P0 is the initial population of the city, t is the time in years, and k is a constant. If the population of the city atis 19,000 and the population of the city atis 23,000, which is the nearest approximation to the population of the city at
Answer:
27,800
Step-by-step explanation:
We need to obtain the initial population(P0) and constant value (k)
Population function : p(t) = P0e^kt
At t = 0, population = 19,000
19,000 = P0e^(k*0)
19,000 = P0 * e^0
19000 = P0 * 1
19000 = P0
Hence, initial population = 19,000
At t = 3; population = 23,000
23,000 = 19000e^(k*3)
23000 = 19000 * e^3k
e^3k = 23000/ 19000
e^3k = 1.2105263
Take the ln
3k = ln(1.2105263)
k = 0.1910552 / 3
k = 0.0636850
At t = 6
p(t) = P0e^kt
p(6) = 19000 * e^(0.0636850 * 6)
P(6) = 19000 * e^0.3821104
P(6) = 19000 * 1.4653739
P(6) = 27842.104
27,800 ( nearest whole number)
Answer:
8^5^7
Step-by-step explanation:
Multiply the numbers:
<u>4</u>X^2 y^3 x <u>2</u>x^3 y^4
<u>8</u>^2 ^3 ^3 ^4
Combine Exponents:
8<u>^2</u> ^3 <u>^3</u> ^4
8<u>^5</u> ^3 ^4
8^5 <u>^3</u> <u>^4</u>
8^5 <u>^7</u>
Answer:
b
Step-by-step explanation: