Pls answer question below.
2 answers:
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The intercepts are the points where the graph crosses the x or y-axis
- <em>The x-intercepts changed from 0 to </em>
<em>.</em>
- <em>The y-intercepts changed from 0 to 3</em>
The functions are given as:
<u>Function f(x)</u>
The x-intercept is calculated as follows:
Set f(x) to 0
Solve for x
The y-intercept is calculated as follows:
Set x to 0
Hence, the intercepts are 0
<u>Function g(x)</u>
The x-intercept is calculated as follows:
Set g(x) to 0
Solve for x
The y-intercept is calculated as follows:
Set x to 0
The x-intercepts are , while the y-intercept is -3
By comparing the intercepts of f(x) and g(x),
- <em>The x-intercepts changed from 0 to </em>
- <em>The y-intercepts changed from 0 to 3</em>
Read more about intercepts at:
Answer:
Lots of connections!
Step-by-step explanation:
I attached some images to make it more clear.
Visual and verbal discussion:
A good starting point is the circle. One can think of a circle as the set of points that are equidistant to a certain point. In that sense, one can define a circle using the distance. At the same time, given a point in the plane, we can connect the point with the origin of the coordinates system forming a rectangle triangle! (See 2nd image)
Algebraic discussion:
1. The distance Formula:
Given two points in the plane and
we can find the distance between both points with the distance formula:
2. Equation of a circle centered at a point
3. The Pythagorean Theorem:
Given a triangle of sides and hypotenuse
we have that
Only by writing this equations we can already see the similarities between all three.
In fact, the most amazing thing about all three is that they are equivalents. That is, we can obtain every single one of them as an immediate result of another.
For instance, as I said before, one can think of a circle as the set of points equidistant to a certain origin or center point. So we could use the distance formula for each point on the circumference and we would obtain always the same value hence obtaining the equation of a circle.
Also as we discussed, any point on the plane form a rectangle triangle with its coordinates and calculating the distance of said point to the origin of the coordinate system would give us no other thing than the hypotenuse of said triangle!
