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Alexeev081 [22]

3 years ago

10

How do you do 6y^2-8y?

1 answer:

zheka24 [161]3 years ago

7 0

You factor out 2y from the situation

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Write the slope-intercept form of the equation of the line through the given points.

9966 [12]

Answer:

y = 7x +2

Step-by-step explanation:

the equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

calculate m using the slope formula

m = $\frac{y_{2}-y_{1} }{x_{2}-x_{1} }$

with (x₁, y₁ ) = (0, 2 ) and (x₂, y₂ ) = (- 1, - 5 )

m = $\frac{-5-2}{-1-0}$ = $\frac{-7}{-1}$ = 7

the line crosses the y- axis at (0, 2 ) ⇒ c = 2

y = 7x + 2 ← equation of line

6 0

2 years ago

What is 0.506 rounded in the hundredths

Aleksandr [31]

0.51 The hundredths place increases when it is higher than or equal to 5 in the thousandths place.

4 0

4 years ago

Read 2 more answers

What is the product in scientific notation?

sashaice [31]

(2.5 × $10^{-10}$ ) × (7 × $10^{-6}$ )

First, simplify brackets. / Your problem should look like: 2.5 × $10^{-10}$ × 7 × $10^{-6}$
Second, simplify. / Your problem should look like: 17.5 × $10^{-10}$ × $10^{-6}$
Third, simplify exponent. / Your problem should look like: 17.5 × $10^{-15}$

Answer: B

3 0

3 years ago

Read 2 more answers

Rewrite as y−k=a(x−h)2 or x−h=a(y−k)2. Find the vertex, focus, and directrix.<br> y−3=(2−x)^2

Talja [164]

Given:

The given equation is

$y-3=(2-x)^2$

To find:

The vertex, focus, and directrix.

Solution:

The equation of a parabola is

$y-k=a(x-h)^2$ ...(i)

where, (h,k) is vertex, $\left(h,k+\dfrac{1}{4a}\right)$ and directrix is $y=k-\dfrac{1}{4a}$

We have,

$y-3=(2-x)^2$

It can be written as

$y-3=(-(x-2))^2$

$y-3=(x-2)^2$ ...(ii)

On comparing (i) and (ii), we get

$h=2,k=3,a=1$

Vertex of the parabola is (2,3).

$Focus=\left(2,3+\dfrac{1}{4(1)}\right)$

$Focus=\left(2,3+\dfrac{1}{4}\right)$

$Focus=\left(2,\dfrac{13}{4}\right)$

Therefore, the focus of the parabola is $\left(2,\dfrac{13}{4}\right)$ .

Directrix of the parabola is

$y=3-\dfrac{1}{4(1)}$

$y=3-\dfrac{1}{4}$

$y=\dfrac{11}{4}$

Therefore, the directrix of the parabola is $y=\dfrac{11}{4}$ .

4 0

3 years ago

What is the answer to the q's

TEA [102]

Answer:

1.TRUE

2.TRUE

3.FALSE

4.TRUE

4 0

4 years ago