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lyudmila [28]
3 years ago
10

A bookshelf has 276 books distributed evenly among 6 shelves. Find the unit rate of books per shelf

Mathematics
1 answer:
nexus9112 [7]3 years ago
8 0

Answer:

46 books

Step-by-step explanation:

276/6=46 books per shelf

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Find the values of the variables for the parallelogram if m<1=4y-2. Round your answers to two decimal places if necessary!
hichkok12 [17]

The prallelogram whose adjacent sides are equal and one vertex angle is 90 degrees is a square.

The value of angle 1 is 90 degrees as the diagonal of the square intersect at 90 degrees.

\begin{gathered} 4y-2=90 \\ 4y=92 \\ y=23 \end{gathered}

The value of y is 23.

The diagonal of the square bisect the vertex angle hence the angle of 3x is 45 degrees.

\begin{gathered} 3x=45 \\ x=15 \end{gathered}

Thus, the value of x is 15 degrees.

The value of 12z is 45 degrees.

\begin{gathered} 12z=45 \\ z=3.75 \end{gathered}

Thus, the required value of z is 3.75 degrees.

3 0
1 year ago
A rectangle has an area of 36 inches squared. Write an equation to show how the length (l) varies inversely the width (w).
Anastaziya [24]
Start with the first sentence, and the definition of the area of a rectangle:
l * w = 36

Rewrite the equation to get
l = 36 / w
or
w = 36 / l
Either one shows the inverse relationship between w and l.

Assuming the last part wants you to write an equation for an x-y graph, the equation would be
y = 36 / x
8 0
3 years ago
Using the simple random sample of weights of women from a data​ set, we obtain these sample​ statistics: nequals45 and x overbar
Tomtit [17]

Answer: (141.1, 156.48)

Step-by-step explanation:

Given sample statistics : n=45

\overline{x}=148.79\text{ lb}

\sigma=31.37\text{ lb}

a) We know that the best point estimate of the population mean is the sample mean.

Therefore, the best point estimate of the mean weight of all women = \mu=148.79\text{ lb}

b) The confidence interval for the population mean is given by :-

\mu\ \pm E, where E is the margin of error.

Formula for Margin of error :-

z_{\alpha/2}\times\dfrac{\sigma}{\sqrt{n}}

Given : Significance level : \alpha=1-0.90=0.1

Critical value : z_{\alpha/2}=z_{0.05}=\pm1.645

Margin of error : E=1.645\times\dfrac{31.37}{\sqrt{45}}\approx 7.69

Now, the 90% confidence interval for the population mean will be :-

148.79\ \pm\ 7.69 =(148.79-7.69\ ,\ 148.79+7.69)=(141.1,\ 156.48)

Hence, the 90​% confidence interval estimate of the mean weight of all women= (141.1, 156.48)

3 0
3 years ago
If r= 37 find the values of p, q, s
kkurt [141]

Answer:

ckfgfuf go he z v g b I g to

Step-by-step explanation:

c I'm x go bc to ggzh it ti

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3 years ago
Helpppp for those who can read bahasa pleaseee
wlad13 [49]

Answer:

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Step-by-step explanation:

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