Question

0%7B2%7D%5E%7Bx%20%2B%201%7D%20-%20%20%7B2%7D%5E%7Bx%20%2B%202%20%7D%20%20%7D%20" id="TexFormula1" title=" \frac{ {2}^{x + 2} - {2}^{ x + 3} }{ {2}^{x + 1} - {2}^{x + 2 } } " alt=" \frac{ {2}^{x + 2} - {2}^{ x + 3} }{ {2}^{x + 1} - {2}^{x + 2 } } " align="absmiddle" class="latex-formula">
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Answer 1

I suppose you just have to simplify this expression.

(2ˣ⁺² - 2ˣ⁺³) / (2ˣ⁺¹ - 2ˣ⁺²)

Divide through every term by the lowest power of 2, which would be x + 1 :

… = (2ˣ⁺²/2ˣ⁺¹ - 2ˣ⁺³/2ˣ⁺¹) / (2ˣ⁺¹/2ˣ⁺¹ - 2ˣ⁺²/2ˣ⁺¹)

Recall that nª / nᵇ = nª⁻ᵇ, so that we have

… = (2⁽ˣ⁺²⁾ ⁻ ⁽ˣ⁺¹⁾ - 2⁽ˣ⁺³⁾ ⁻ ⁽ˣ⁺¹⁾) / (2⁽ˣ⁺¹⁾ ⁻ ⁽ˣ⁺¹⁾ - 2⁽ˣ⁺²⁾ ⁻ ⁽ˣ⁺¹⁾)

… = (2¹ - 2²) / (2⁰ - 2¹)

… = (2 - 4) / (1 - 2)

… = (-2) / (-1)

… = 2

Another way to get the same result: rewrite every term as a multiple of y = 2ˣ :

… = (2²×2ˣ - 2³×2ˣ) / (2×2ˣ - 2²×2ˣ)

… = (4×2ˣ - 8×2ˣ) / (2×2ˣ - 4×2ˣ)

… = (4y - 8y) / (2y - 4y)

… = (-4y) / (-2y)

… = 2