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Anvisha [2.4K]
3 years ago
6

Hi can anybody explain to me how to do this I'm kinda confused . 5×[5(-7)]​

Mathematics
1 answer:
telo118 [61]3 years ago
4 0

Answer:

5 × [5(-7)]

= 5 × (-35)   ---- 5 × (-7) = -35

= -175

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Given radical a and radical b are in simplest radical form and radical a timed radical b equals c radical d and c radical d is i
lawyer [7]

Answer:

See below.

Step-by-step explanation:

Since sqrt(a) and sqrt(b) are in simplest radical form, that means a and b have no perfect square factors. When sqrt(a) and sqrt(b) are multiplied giving c * sqrt(d), the fact that c came out of the root means that there was c^2 inside the product sqrt(ab). This means that a and b have at least one common factor.

ab = c^2d

Example:

Let a = 6 and let b = 10.

sqrt(6) and sqrt(10) are in simplest radical form.

Now we multiply the radicals.

sqrt(a) * sqrt(b) = sqrt(6) * sqrt(10) = sqrt(60) = sqrt(4 * 15) = 2sqrt(15)

We have c = 2 and d = 15.

ab = c^2d

6 * 10 = 2^2 * 15

60 = 60

Our relationship between a, b and c, d works.

6 0
3 years ago
Simplify this expression
qaws [65]

Answer:

10

Step-by-step explanation:

25-10+3-8

15+3-8

18-8

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6 0
3 years ago
5 ( 3 squared x) + 9 ( 3 squared x)
yulyashka [42]

Answer:

42x^2

Step-by-step explanation:

5(3x^{2} )+9(3x^2)\\\\=(5+9)(3x^2)\\\\=14(3x^2)\\\\=42x^2

5 0
3 years ago
Which expression is equivalent to (2x to 4 y) 3 exponent?
nirvana33 [79]
I’m pretty sure it’s b
5 0
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10. A weight hangs on a spring. The vibration period of that weight is the time in which it makes a complete cycle in motion. Su
Alenkinab [10]

The vibration period of the spring will be 0.2 seconds

<em><u>Explanation </u></em>

The relationship between the vibration period "T" (in seconds) and the weight "w" (in kilograms) is given by...

T= 2\sqrt{\frac{w}{200}}

Given that, the weight(w) = 2.0 kilograms

So, <u>plugging w = 2.0</u> into the above equation, we will get...

T= 2\sqrt{\frac{2.0}{200} } \\ \\ T= 2\sqrt{\frac{1}{100} }\\ \\ T= 2*\frac{1}{10}\\ \\ T= \frac{1}{5}=0.2

So, the vibration period of the spring will be 0.2 seconds.

8 0
3 years ago
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