Given expressions:
Area of a rectangle = L W
Area of a triangle = 
Problem;
Create problems using the formula;
Solution:
Problem 1; Find the area of a rectangle whose length is 10cm and the width is half the size of the length?
Given parameters:
Length of rectangle = 10cm
Width of rectangle =
x length =
x 10 = 5cm
So, the area of the rectangle = 10cm x 5cm = 50cm²
2. A triangle with a base length of 30cm and a height of 2cm will have an area of what?
Given parameters:
base length = 30cm
height = 2cm
Solution:
Area of a triangle =
x b x h
Area of a triangle =
x 30 x 2 = 30cm²
The area of the triangle will be 30cm²
Answer:
868 m³
Step-by-step explanation:
Volume = Difference of cones
V = ⅓(pi×r²h)
Volume of cone with base Circle O:
h = 8.2+8.2 = 16.4 m
V1 = ⅓(pi×7.6²×16.4)
V1 = 991.97
Volume of cone with base Circle A:
V2 = ⅓(pi×3.8²× 8.2)
V2 = 124 m³
Volume = V1 - V2
991.97 - 124 = 868 m³
Given:
The area of the rectangle RSTU = 
Length of the rectangle RSTU = 
To find:
The width of the rectangle RSTU.
Step-by-step explanation:
We have,

Splitting the middle term, we get



We know that, the area of a rectangle is

Area of rectangle is product of (4x+5) and (9x-5).
Since (4x+5) is the length of the rectangle, therefore, (9x-5) is the width of the rectangle RSTU.
Answer:
varied
square root of number never result negative number
Step-by-step explanation: