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almond37 [142]
2 years ago
12

In geometry what is the purpose of sin and cos?​

Mathematics
2 answers:
marishachu [46]2 years ago
8 0

Answer:

sin is the ratio of the opposite side to the hypotenuse

cos is the ratio of the adjacent side to the hypotenuse

Brainiest plz

Rasek [7]2 years ago
5 0
Sin cos and tan are basically just functions that relate an angle with a ratio of two sides in a right triangle. Sin is equal to the side opposite the angle that you are conducting the functions on over the hypotenuse which is the longest side in the triangle. Cos is adjacent over hypotenuse.
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8 0
3 years ago
A team of 5 runners competed in a relay race. Each runner had to run 730 yards. How long was the race? (ANSWER IF YOU KNOW AND H
Naya [18.7K]

Answer:

3650 yds

Step-by-step explanation:

Take the length that each person ran and multiply by the number of runners

5 * 730yds

3650 yds

6 0
2 years ago
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If a teacher had 10 percent of her students fail, how many would that be if she had 130 students
Nimfa-mama [501]

Answer:

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3 years ago
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How mant calories will darrel burn in 1 minute ?
s344n2d4d5 [400]

Answer:

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Step-by-step explanation:

5 0
3 years ago
Find the equation of a straight line passing throught the point listed and having the given gradient. Express your answer in the
Igoryamba
First let's try to find the equation in this form : <span>y = mx + c 

The gradient is given 3 . In a line's equation, x's coefficient represents the line's gradient.

So equation of a line with the gradient of 3, would look like this ;

</span>y= 3x + c
<span>
Now a point that the line passes through is given, (1, 2) 

This point's x-coordinate is 1 and y-coordinate is 2.

So we'll plug its x-coordinate value in the equation and also y-coordinate value. So we can solve it.

As you know, </span>x=1 and y=2

y = 3x + c

2\quad =\quad 3\cdot 1+c\\ \\ 2\quad =\quad 3+c\\ \\ 2-3\quad =\quad c\\ \\ -1\quad =\quad c

We found c = -1 

Also in a line's equation, c is constant and it represents the line's y-intercept

So let's build the line's equation.

m=3 and c=-1

y= mx + c

y= 3x -1

We found the line's equation in this form, y= mx + c

Now let's turn it into this form, ax + by + c = 0

y\quad =\quad 3x-1\\ \\ y-3x\quad =\quad -1\\ \\ y-3x+1\quad =\quad 0\\ \\ -3x+y+1\quad =\quad 0

Final answers,

\boxed { y\quad =\quad 3x-1 }

and 

\boxed { -3x+y+1\quad =\quad 0 }

I hope this was clear enough :)




<span>


</span>
5 0
3 years ago
Read 2 more answers
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