Let the first brother = x
second brother = x + 2
third brother = x + 4
<span>The product of the first and third boys' ages is 20 more than twice the second boy's age:
x(x+4) = 2(x+2) + 20
x</span>² + 4x = 2x + 4 + 20
x² + 4x - 2x - 24 = 0
x² + 2x - 24 = 0
(x - 4)(x + 6) = 0
x = 4 or -6 (rejected, age cannot be negative)
First brother = 4
Second brother = 4 + 2 = 6
Third brother = 4 + 4 = 8
The three boys are 4, 6, and 8 years old.
The answer is 96.
The 3,a,b,& c cancel out because they equal 1.
Then your left with 48*2 which is 96.
48 * a * 3 * b * c * 2--------------------------3 * a * b * c
3/3 = 1 B/b = 1 C/c = 1
1 * 1 * 1 * 48 * 2 = 96
Answer:
4n-13
Step-by-step explanation:
Terms= -13 (constant)
Coefficient= 3, -5, 6
Like term= 3n, -5n, 6n
3n-13-5n+6n
3n+6n-5n-13
9n-5n-13
4n-13
Hope this helps ;) ❤❤❤
Answer:
$28.3
Step-by-step explanation:
x=rate for 1km
y=initial fee
Mike: $35 for 15km -> 35 = 15x + y
Thomas: $24.50 for 10km -> 24.50 = 10x + y
Using those two equations we see the following:
Mike paid $10.5 more for 5 more km. The initial fee remains unchanged, so we can calculate the rate for 1km, which is 10.5/5=2.1.
35 = 15x + y
24.50 = 10x + y
10.5 = 5x
2.1=x
Using that value with one of the original equations we can calculate the initial fee.
35 = 15x + y
35 = 15*2.1 + y
35 = 31.5 + y
3.5 = y
Mike paid 15*2.1=31.5 ($2.1 for every km) plus the initial fee, his total was $35.
We subtract the 31.5 from the 35(total) and get the initial fee, which is $3.5.
<u>Let's see what Lex will pay:</u>
Km travelled times 2.1 (the rate for 1km) plus 3.5 (the initial fee).
12*2.1 + 3.5 = 28.3
Lex will pay $28.3 for the same taxi company to travel 12 km.
I wrote the algebraic expressions in order for you. When I show the up arrow, it represents that the number after the arrow is an exponent. Hopefully this helps. :D
4 • (n^3 - 7)
(5 x n) + 3
(n^2) - 15
3 + (5 x y)
