Question

Use the box plots comparing the number of male dogs and number of dogs attending doggy daycare each day for a month to answer the questions.
Two box plots shown. The top one is labeled Males. Minimum at 0, Q1 at 3, median at 10, Q3 at 15, maximum at 35. The bottom box plot is labeled Females. Minimum at 0, Q1 at 2, median at 6, Q3 at 9, maximum at 14, and a point at 31.

Part A: Estimate the IQR for the males' data. (2 points)

Part B: Estimate the difference between the median values of each data set. (2 points)

Part C: Describe the distribution of the data and if the mean or median would be a better measure of center for each. (4 points)

Part D: Provide a possible reason for the outlier in the data set. (2 points)

Answer 1

The outliers of a boxplot are data points that are not in the whiskers of the boxplot

The given parameters are:

Male do gs

• Minimum = 0
• Lower quartile, Q1 = 3
• Median, Q2 = 10
• Upper quartile, Q3 = 15
• Maximum = 35.

Female do gs

• Minimum = 0
• Lower quartile, Q1 = 2
• Median, Q2 = 6
• Upper quartile, Q3 = 9
• Maximum = 14
• Outlier = 31.

Part A: The IQR for the male's data

This is calculated as:

$IQR =Q_3 - Q_1$

So, we have:

$IQR =15 - 3$

$IQR =12$

Hence, the IQR for the male's data is 12

Part B: The difference in their median

This is calculated as:

$d = Q_2(male) -Q_2(female)$

So, we have:

$d = 10 - 6$

$d = 4$

Hence, the difference between the median value of each data is 4

Part C: The distribution of the data

The distribution of the male's data is not affected by outlier, while the distribution of the female's data is affected by outlier

Hence, the mean is a better measure of center for the male's distribution while the median is a better measure of center for the female's distribution

Part D: Reason for outlier

The possible reason for the outlier in the dataset could be as a result of natural variation in the breeds

Read more about boxplots and outliers at:

brainly.com/question/14277132