1. AB/EF = P(ABCD)/P(EFGH)
4/5=16/P(EFGH)
P(EFGH)=5*16/4=5*4=20
2. V(old)=lwh =
V(new)=2*l*2*w*2*h =2³(lwh)=2³*V(old)= 8*3600=28800
3. A(old)=ab
A(new)=5a*5b=25ab=25A(old)
new area will be 25 times larger
Take out a GCF (greatest common factor, which is 3x) factor what is left, (x^2 - 4)
Please respond if you understand, or if you need more help!
Answer:
Hi there!
The Answer to this question is: 3897/100
The only way a linear (line) graph could have more than 2 intercecting points is if the equations were the same like
y=2x+4 and 2y=4x+8
That's 2³ = 8 that gives the number of subsets
