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2 years ago

-3x - 6 greater than 15

1 answer:

4 0

The answer should be X<7! You start by add the 6, then dividing my -3! When you divide by a negative you change the sign!

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What is ( 13824 - 11 ) x 9

nexus9112 [7]

[ Answer ]

$\boxed{124317}$

[ Explanation ]

(13824 - 11) * 9

Parenthesis

Exponents

Multiply

Divide

Add

Subtract

13824 - 11 = 13813

Multiply

13813 * 9 = 124317

$\boxed{[ \ Eclipsed \ ]}$

8 0

2 years ago

Read 2 more answers

For a certain river, suppose the drought length Y is the number of consecutive time intervals in which the water supply remains

AnnZ [28]

Answer:

a) There is a 9% probability that a drought lasts exactly 3 intervals.

There is an 85.5% probability that a drought lasts at most 3 intervals.

b)There is a 14.5% probability that the length of a drought exceeds its mean value by at least one standard deviation

Step-by-step explanation:

The geometric distribution is the number of failures expected before you get a success in a series of Bernoulli trials.

It has the following probability density formula:

$f(x) = (1-p)^{x}p$

In which p is the probability of a success.

The mean of the geometric distribution is given by the following formula:

$\mu = \frac{1-p}{p}$

The standard deviation of the geometric distribution is given by the following formula:

$\sigma = \sqrt{\frac{1-p}{p^{2}}$

In this problem, we have that:

$p = 0.383$

$\mu = \frac{1-p}{p} = \frac{1-0.383}{0.383} = 1.61$

$\sigma = \sqrt{\frac{1-p}{p^{2}}} = \sqrt{\frac{1-0.383}{(0.383)^{2}}} = 2.05$

(a) What is the probability that a drought lasts exactly 3 intervals?

This is $f(3)$

$f(x) = (1-p)^{x}p$

$f(3) = (1-0.383)^{3}*(0.383)$

$f(3) = 0.09$

There is a 9% probability that a drought lasts exactly 3 intervals.

At most 3 intervals?

This is $P = f(0) + f(1) + f(2) + f(3)$

$f(x) = (1-p)^{x}p$

$f(0) = (1-0.383)^{0}*(0.383) = 0.383$

$f(1) = (1-0.383)^{1}*(0.383) = 0.236$

$f(2) = (1-0.383)^{2}*(0.383) = 0.146$

Previously in this exercise, we found that $f(3) = 0.09$

$P = f(0) + f(1) + f(2) + f(3) = 0.383 + 0.236 + 0.146 + 0.09 = 0.855$

There is an 85.5% probability that a drought lasts at most 3 intervals.

(b) What is the probability that the length of a drought exceeds its mean value by at least one standard deviation?

This is $P(X \geq \mu+\sigma) = P(X \geq 1.61 + 2.05) = P(X \geq 3.66) = P(X \geq 4)$ .

We are working with discrete data, so 3.66 is rounded up to 4.

Either a drought lasts at least four months, or it lasts at most thee. In a), we found that the probability that it lasts at most 3 months is 0.855. The sum of these probabilities is decimal 1. So:

$P(X \leq 3) + P(X \geq 4) = 1$

$0.855 + P(X \geq 4) = 1$

$P(X \geq 4) = 0.145$

There is a 14.5% probability that the length of a drought exceeds its mean value by at least one standard deviation

8 0

3 years ago

Has a slope of 1/2 and passes<br> through the point (-2, 4).<br> Need the equation please

nikklg [1K]

Answer: Mark me brainliest..

Step-by-step explanation: and imma put the answer inside the comments if you do so. youve got nothing to lose! :D

5 0

2 years ago

Read 2 more answers

Explain how I would get -7 from dividing -45 from 7 Full explanation gets brainly

lana66690 [7]

If you divide a negative by a positive then you get a negative or if you divide a positive by a negative then you make that number negative

3 0

2 years ago

CAN SOMEONE PLEASE HELP WITH THIS <br><br> ITS USING THE DISTRIBUTIVE PROPERTY PLEASE HELP

maw [93]

Answer:

1) 3x+3y-12

2) 4a-4b

4) 7t-98

5) 6x-54

7) 8m-4n

8) -3x+18y

3 0

3 years ago