I think it would be b) because you're given a slope of 0, so that leaves you with
, resulting into this
You'd be just left with a continuous horizontal line going through the y-axis of 3 since you're passing the point (2,3), where 3 represents the y-value when your slope is at 0.
Answer:
Option A.
Step-by-step explanation:
step 1
we know that
The equation of the solid line is
The solution is the shaded area above the solid line
so
The equation of the first inequality is
step 2
The equation of the dashed line is
The solution is the shaded area above the dashed line
so
The equation of the second inequality is
therefore
The system of inequalities could be
I believe the correct given problem is:
“What is 80% in its simplest form as a fraction?”
Take note that you missed to place the percent sign which
is very important.
Now to solve this, 80% when converted to decimal form is
0.80 which means that you have 80 parts per 100 parts. Therefore the fraction
form of this would be 80 / 100.
fraction = 80 / 100
However this fraction is not yet the answer because we
can still simplify this further. First step in simplifying is to divide both
the numerator and denominator by 10 so that we are left with:
8 / 10
Next step is to divide by 2:
4 / 5
Now we can see that we can no longer divide this (numbers
should be whole number). Therefore the simplest form as a fraction is 4/5
Answer:
4/5
D) Vertices: (1, -1), (-11, -1); Foci: (-15, -1), (5, -1)
Answer:
![\left[\begin{array}{ccc}3&-1&\\-1&1/2\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D3%26-1%26%5C%5C-1%261%2F2%5C%5C%5Cend%7Barray%7D%5Cright%5D)
Step-by-step explanation:
The matrix system for the linear equations: x + 2y = 8, 2x + 6y = 9
![\left[\begin{array}{ccc}1&2&\\2&6\\\end{array}\right] \left[\begin{array}{ccc}x\\y\end{array}\right] = \left[\begin{array}{ccc}8\\9\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%262%26%5C%5C2%266%5C%5C%5Cend%7Barray%7D%5Cright%5D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Dx%5C%5Cy%5Cend%7Barray%7D%5Cright%5D%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D8%5C%5C9%5Cend%7Barray%7D%5Cright%5D)
To get the coefficient of x and y, the inverse of the first matrix (let the first matrix be A) must be known.
= (1 / determinant of A) x Adjoint of A
the determinant of A = (1 x 6) - (2 x 2) = 6 - 4 = 2
Adjoint of A = ![\left[\begin{array}{ccc}6&-2&\\-2&1\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D6%26-2%26%5C%5C-2%261%5C%5C%5Cend%7Barray%7D%5Cright%5D)
= ![\frac{1}{2} \left[\begin{array}{ccc}6&-2\\-2&1\end{array}\right]](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D6%26-2%5C%5C-2%261%5Cend%7Barray%7D%5Cright%5D)
=
