3 years ago

Use the tangent ratio to find x in the picture attached.

Mathematics

1 answer:

Sedbober [7]3 years ago

4 0

Sry that I can’t answer but I hope u have a great day
Yxucivb:)

You might be interested in

What is the square root of negative four

Dmitry [639]

The square root of negative four is 2

3 0

3 years ago

What is the length of this segment ?

FinnZ [79.3K]

1 $\frac{11}{16}$ is the answer you're looking for.

6 0

3 years ago

Write an expression for the measurement of angle L using the measurement of angle C found in part C

kap26 [50]

Answer:

180’ - 130’

Step-by-step explanation:

3 0

3 years ago

At the city museum, child admission is $5.10 and adult admission is $9.70 . On Monday, twice as many adult tickets as child tick

Alexeev081 [22]

31. I'm not positive but give it a shot if it is wrong message me back!

6 0

3 years ago

Read 2 more answers

A projectile is launched into the air. The function h(t) = –16t2 + 32t + 128 gives the height, h, in feet, of the projectile t s

Zinaida [17]

Answer:

t = 4 seconds

Step-by-step explanation:

The height of the projectile after it is launched is given by the function :

$h(t)=-16t^2+32t+128$

t is time in seconds

We need to find after how many seconds will the projectile land back on the ground. When it land, h(t)=0

So,

$-16t^2+32t+128=0$

The above is a quadratic equation. It can be solved by the formula as follows :

$t=\dfrac{-b\pm \sqrt{b^2-4ac} }{2a}$

Here, a = -16, b = 32 and c = 128

$t=\dfrac{-32\pm \sqrt{(32)^2-4\times (-16)(128)} }{2\times (-16)}\\\\t=\dfrac{-32+ \sqrt{(32)^2-4\times (-16)(128)} }{2\times (-16)}, \dfrac{-32\- \sqrt{(32)^2-4\times (-16)(128)} }{2\times (-16)}\\\\t=-2\ s\ \text{and}\ 4\ s$

Neglecting negative value, the projectile will land after 4 seconds.

4 0

3 years ago