Find the negation of statement <br>2+5=5

The perimeter of a rectangle is 15x + 17y. If the length is 7/2x + 7y then find the width of the rectangle.

EastWind [94]

Answer:

84 c. –25 6. 119 7. –28 36 8a. 4 b. 52 LESSON EI.B: ANSWERS 709 Topic EI .... The length is 11 inches, and the width is 7 inches. ... 15x – 10 = 2x + 6 1 5 10. x = 1 11. y = 8x – 5 12. x = y + 8 8 49. .... 5xy 3 – 17x 2y + 8xy + 16x 3y – 7x 10. x 3y 2z – 10x 2y + 14x 2z + 3xy 2 – 25xz 2 LESSON ... 2 > y > –5 F a 4x 3 y 5 4y 3 x 22.

Step-by-step explanation:

5 0

3 years ago

Pls answer quickly. Thanks!

Gwar [14]

Answer:

the answer is D

Step-by-step explanation:

4 0

3 years ago

Can someone please give me the answers to this? ... please ...

Hoochie [10]

Step-by-step explanation:

come on ! based on all the other questions that have been answered AND explained you should be able to find these answers yourself now. what is still unclear ?

distance between 2 points (x1, y1) and (x2, y2):

Pythagoras : c² = a² + b²

c is the connection between the 2 points (and which length we need to find).

c = sqrt(a² + b²)

a and b are differences of the x coordinates and the differences of the y coordinates of these 2 points.

a = x1 - x2

b = y1 - y2

this is simply because, when you look at the coordinate grid, these 3 items make a right-angled triangle.

don't worry about any negative values for a and b, as the square eliminates the negative sign.

midpoint between 2 points :

we could use Pythagoras again for this, but the end result is so simple, we can skip this.

at the end the coordinates of the midpoint of 2 points (x1, y1) and (x2, y2) are

((x1+x2)/2, (y1+y2)/2)

find the other endpoint (x2, y2), when you have one endpoint (x1, y1) and the midpoint (xm, ym) :

from above you know

xm = (x1+x2)/2

2×xm = x1 + x2

x2 = 2×xm - x1

and in the same way

ym = (y1+y2)/2

2×ym = y1 + y2

y2 = 2×ym - y1

and you can read a graph, right ?

if not it is high time to learn that very simple and basic skill :

the x coordinate of a point is how many units right (positive) or left (negative) from the center point it is.

the y coordinate of a point is how many units above (positive) or below (negative) from the center point it is.

the center point is always (0, 0).

so, what else do you need ?

I am very busy explaining things. I should not spend my little time doing the basic calculations for you (that I could train a monkey to do).

so, please, oil your brain machinery by following the instructions and formulas using the actual numbers and see how the results build out of this.

if you run into further problems, please ask me for additional explanations.

8 0

3 years ago

A rectangular swimming pool is bordered by a concrete patio. the width of the patio is the same on every side. the area of the s

andre [41]

Answer:

$x = \frac{1}{4}\left(-(l + w) + \sqrt{l^2 + 6lw + w^2} \right)$

where

l = length of the pool (w/o the patio)
w = width of the pool (w/o the patio)

Explanation:

Let

x = width of the patio
l = length of the pool (w/o the patio)
w = width of the pool (w/o the patio)

Since the pool is bordered by a complete patio,

Length of the pool (with the patio)
= (length of the pool (w/o the patio)) + 2*(width of the patio)
Length of the pool (with the patio) = l + 2x

Width of the pool (with the patio)
= (width of the pool (w/o the patio)) + 2*(width of the patio)
Width of the pool (with the patio) = w + 2x

Note that

Area of the pool (w/o the patio)
= (length of the pool (w/o the patio))(width of the pool (w/o the patio))
Area of the pool (w/o the patio) = lw

Area of the pool (with the patio)
= (length of the pool (w/o the patio))(width of the pool (w/o the patio))
= (l + 2x)(w + 2x)
= w(l + 2x) + 2x(l + 2x)
= lw + 2xw + 2xl + 4x²
Area of the pool (with the patio) = 4x² + 2x(l + w) + lw

Area of the patio
= (Area of the pool (with the patio)) - (Area of the pool (w/o the patio))
= (4x² + 2x(l + w) + lw) - lw
Area of the patio = 4x² + 2x(l + w)

Since the area of the patio is equal to the area of the surface of the pool, the area of the patio is equal to the area of the pool without the patio. In terms of the equation,

Area of the patio = Area of the pool (w/o the patio)
4x² + 2x(l + w) = lw
4x² + 2x(l + w) - lw = 0 (1)

Let

a = numerical coefficient of x² = 4
b = numerical coefficient of x = 2(l + w)
c = constant term = -lw

Then using quadratic formula, the roots of the equation 4x² + 2x(l + w) - lw = 0 is given by

$x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}
\\ = \frac{-2(l + w) \pm \sqrt{(2(l + w))^2 - 4(4)(-lw)}}{2(4)} 
\\ = \frac{-2(l + w) \pm \sqrt{(4(l + w)^2) + 16lw}}{8} 
\\ = \frac{-2(l + w) \pm \sqrt{(4(l^2 + 2lw + w^2) + 4(4lw)}}{8}
\\ = \frac{-2(l + w) \pm \sqrt{(4(l^2 + 2lw + w^2 + 4lw)}}{8}
\\ = \frac{-2(l + w) \pm \sqrt{(4(l^2 + 6lw + w^2)}}{8}$
$= \frac{-2(l + w) \pm 2\sqrt{l^2 + 6lw + w^2}}{8} \\= \frac{2}{8}(-(l + w) \pm \sqrt{l^2 + 6lw + w^2}) \\x = \frac{1}{4}(-(l + w) \pm \sqrt{l^2 + 6lw + w^2}) \\\boxed{x = \frac{1}{4}\left(-(l + w) + \sqrt{l^2 + 6lw + w^2} \right) \text{ or }}
\\\boxed{x = -\frac{1}{4}\left((l + w) + \sqrt{l^2 + 6lw + w^2} \right)}$

Since $(l + w) + \sqrt{l^2 + 6lw + w^2} \ \textgreater \ 0$ , $-\frac{1}{4}\left((l + w) + \sqrt{l^2 + 6lw + w^2}\right)$ is negative. Since x represents the patio width, x cannot be negative. Hence, the patio width is given by

$\boxed{x = \frac{1}{4}\left(-(l + w) + \sqrt{l^2 + 6lw + w^2} \right)}$

7 0

3 years ago

Order 2.000 D5W IV to infuse over 12 hoursThe drop factor is 15 gtt/. Calculate the rate in gtt / min

PilotLPTM [1.2K]

Answer:

42gtt/m

Step-by-step explanation:

According to the scenario, computation of the given data are as follows,

Flow rate in gtt/min = (Total fluid in ml × Drop factor) ÷ (Total hours × 60)

Where, Total fluid in ml = 2,000ml

Drop factor = 15gtt/m

Total hours = 12hours

By putting the following value in the formula, we get

Flow rate in gtt/min = (2,000 × 15) ÷ (12 × 60)

= 30,000 ÷ 720

= 41.67 or 42gtt/m

5 0

3 years ago

Find the negation of statement 2+5=5​

Find the negation of statement 2+5=5