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Ymorist [56]
3 years ago
14

In June 2009, at the trough of the Great Recession, the Bureau of Labor Statistics (BLS) announced that of all adult Americans,

140,196,000 were employed, 14,729,000 were unemployed, and 80,729,000 were not in the labor force. What is the adult population? 14,729,000 140,196,000 154,925,000 235,654,000
Mathematics
2 answers:
VashaNatasha [74]3 years ago
8 0

The Bureau of Labor Statistics (BLS)  report says that 140,196,000 were employed, 14,729,000 were unemployed, and 80,729,000 were not in the labor force.

And then the question asks for the total adult population .

To find the total adult population we have to just add all the numbers given

that is

employed + unemployed + those who are not in the labor force

So 140,196,000+14,729,000+80,729,000

= 235,654,000

So Option D is the correct answer.


vladimir2022 [97]3 years ago
4 0
The adult population is 235,634,000.

We find this by adding all of the amounts given:
140196000+14729000+80729000 = 235634000
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Answer:

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80-20=60

60/5=12

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You roll a pair of honest dice. If you roll a total of 7, you win $18; if you roll a total of 11, you win $54; if you roll any o
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The negative value indicates a loss

============================================================

Explanation:

Define the three events
A = rolling a 7
B = rolling an 11
C = roll any other total (don't roll 7, don't roll 11)

There are 6 ways to roll a 7. They are
1+6 = 7
2+5 = 7
3+4 = 7
4+3 = 7
5+2 = 7
6+1 = 7
Use this to compute the probability of rolling a 7
P(A) = (number of ways to roll 7)/(number total rolls) = 6/36 = 1/6
Note: the 36 comes from 6*6 = 36 since there are 6 sides per die

There are only 2 ways to roll an 11. Those 2 ways are:
5+6 = 11
6+5 = 11
The probability for event B is P(B) = 2/36 = 1/18

Since there are 6 ways to roll a "7" and 2 ways to roll "11", there are 6+2 = 8 ways to roll either event. 
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P(C) = 28/36 = 7/9

-----------------------------

In summary so far,
P(A) = 1/6
P(B) = 1/18
P(C) = 7/9

The winnings for each event, let's call it W(X), represents the prize amounts.
Any losses are negative values
W(A) = amount of winnings if event A happens 
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W(A) = 18
W(B) = 54
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Multiply the probability P(X) values with the corresponding W(X) values
P(A)*W(A) = (1/6)*(18) = 3
P(B)*W(B) = (1/18)*(54) = 3
P(C)*W(C) = (7/9)*(-9) = -7

Add up those results
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The expected value for this game is -1.
The player is expected to lose on average 1 dollar per game played.


Note: because the expected value is not 0, this is not a fair game.


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