3 years ago

Which of the following would represent the first step in simplifying the problem 7 divided by 5 (6—2) divided by 2 ?

Mathematics

1 answer:

Dvinal [7]3 years ago

3 0

Answer:

7+5(4) divided by 2

Step-by-step explanation:

this is what i would do because of BEDMAS

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How do you rewrite -82/5 as a decimal

ycow [4]

Just divide -82 by 5.

-82 / 5 = -16.4

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An airplane takes off and then climbs 2500 feet. After 20 minutes, the airplane drops 150 feet.

grigory [225]

Answer:

2350 feet

Step-by-step explanation:

2500-150=2350

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3 years ago

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Step-by-step explanation:

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3 years ago

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Stella [2.4K]

5z - 3 - 3z - 8
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3 years ago

Find all the zeros of 2x4+x3-14x2-19x-6 two of its zeros are -2 and -1

GalinKa [24]

Answer:

$-2,\ -1,\ -\dfrac{1}{2},\ 3.$

Step-by-step explanation:

Consider polynomial $2x^4+x^3-14x^2-19x-6.$

If x=-2 is its zero, then you can divide the polynomial $2x^4+x^3-14x^2-19x-6$ by $x+2$ and get

$2x^4+x^3-14x^2-19x-6=(x+2)(2x^3-3x^2-8x-3).$

If x=-1, then the polynomial $2x^4+x^3-14x^2-19x-6$ can be rewritten as

$2x^4+x^3-14x^2-19x-6=(x+2)(x+1)(2x^2-5x-3).$

The quadratic polynomial has roots

$x_{1,2}=\dfrac{-(-5)\pm\sqrt{(-5)^2-4\cdot2\cdot(-3)}}{2\cdot 2}=\dfrac{5\pm \sqrt{25+24}}{4}=\dfrac{5\pm \sqrt{49}}{4}=3,-\dfrac{1}{2}.$

Then the polynomial $2x^4+x^3-14x^2-19x-6$ has zeros $-2,\ -1,\ -\dfrac{1}{2},\ 3.$

7 0

3 years ago