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Delicious77 [7]
3 years ago
14

PLEASE HELP DONT ANSWER IF YOU DONT KNOW....

Mathematics
2 answers:
Damm [24]3 years ago
4 0

Answer:

5.7 Round it and you will get that

Alex777 [14]3 years ago
3 0

Answer:

cant see pic

Step-by-step explanation:

reply with what it says :) awnser :

5.7

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Guys I really need help plsss
timama [110]

Answer:

x = 3

Step-by-step explanation:

Multiply the first equation by -1, then add it to second equation.

 2x+9y = -12

-2x-7y = 8

-------------------

 2y = -4

Solve for y

2y = -4

y = -2

Plug value of y into one of the equations and solve for x

2x + 9(-2) = -12

2x  = 6

x = 3

5 0
3 years ago
Name the polynomial and number of terms.<br> 10v4 +5v2 + 2v-5
IrinaK [193]

Answer:

Trinomial

Step-by-step explanation:

The given polynomial is a trinomial because it has three terms.

<em>10v4 </em>+<em>5v2 </em>+ <em>2v-5</em>

Hope this helps.

3 0
3 years ago
Furniture Warehouse was having a 35% off of everything sale, so Rhonda bought a folding chair and a small area rug for her new d
notsponge [240]
I wrote it down and it would be too difficult to type but i hope this helps

8 0
3 years ago
Identify the rational exponent expression for V10°.
Alexeev081 [22]

Answer:

The square root of 16 is rational.

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Show that in any group of 101 people there are at least two persons having the same number friends (It is assumed that if a pers
vladimir1956 [14]

Answer:

Step-by-step explanation:

Let us assume that if possible in the group of 101, each had a different number of friends.  Then the no of friends 101 persons have 0,1,2,....100 only since number of friends are integers and non negative.

Say P has 100 friends then P has all other persons as friends.  In this case, there cannot be any one who has 0 friend.  So a contradiction.  Hence proved

Part ii: EVen if instead of 101, say n people are there same proof follows as

if different number of friends then they would be 0,1,2...n-1

If one person has n-1 friends then there cannot be any one who does not have any friend.

Thus same proof follows.

7 0
4 years ago
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