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2 years ago

How do I put 1000,000+200,000+50,000+4,000+300+80+9 in expanded form

Mathematics

1 answer:

MAXImum [283]2 years ago

4 0

If you mean making them a regular number, you add them all.

_______________

But, the expanded form of this is

1,000,000 - Millions Place

200,000 - Hundred Thousands

50,000 -Ten Thousands

4,000 -Thousands

300 - Hundreds

80 -Tens

9 - Ones

I hope this helps, if it doesn't let me know and I'll do my best.

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Please i need help :(

Nezavi [6.7K]

Answer:

37 units

Step-by-step explanation:

$\boxed{distance = \sqrt{(x2 - x1)^{2} + (y2 - y1)^{2} }}$

Using the distance formula above,

distance between (15, -17) and (-20, -5)

$= \sqrt{[15 - ( - 20)]^{2} + [ - 17 - ( - 5)] {}^{2} } \\ = \sqrt{(15 + 20)^{2} + ( - 17 + 5)^{2} } \\ = \sqrt{35 ^{2} + ( - 12) {}^{2} } \\ = \sqrt{1225 + 144} \\ = \sqrt{1369} \\ = 37 \: units$

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2 years ago

A certain model car has a keypad with 5 numbers on the door. To open the door, 5 numbers must be entered in the correct

MrRissso [65]

Answer: A. $\dfrac{1}{120}$

Step-by-step explanation:

Total digits on keypad = 5

According to permutation,

If repetition of digits is not allowed then the number of 5-digits passwords can be formed = 5!

= 5 x 4 x 3 x 2 x 1 [n!=n x (n-1) x (n-2)x ... x 1]

=120

The probability that someone guesses the correct code = $\dfrac{\text{Number of correct codes}}{\text{Total possible codes}}$

$=\dfrac{1}{120}$

Hence, the correct option is A.

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3 years ago

How do I delete this question? I did not mean to ask it.

Brilliant_brown [7]

Answer:

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Step-by-step explanation:

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3 years ago

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Sanjay graphs a quadratic function that has x-intercepts of –3 and 7. Which functions could he have graphed?

kykrilka [37]

we will select each options and find zeros

(a)

$g(x)=x^2-4x-21$

for finding x-intercept , we can set g(x)=0

and then we can solve for x

$g(x)=x^2-4x-21=0$

now, we can factor it

$(x-7)(x+3)=0$

we get

$x=7,x=-3$

so, this is TRUE

(b)

$g(x)=(x-3)(x+7)$

we can set it to 0

and then we can solve for x

$g(x)=(x-3)(x+7)=0$

we get

$x=3,x=-7$

so, this is FALSE

(c)

$g(x)=3x^2-12x-63$

we can set it to 0

and then we can solve for x

$g(x)=3x^2-12x-63 =0$

$3(x^2-4x-21) =0$

$3(x-7)(x+3) =0$

$x=-3,x=7$

so, this is TRUE

(d)

$g(x)=-(x+3)(x-7)$

now, we can set it to 0

and then we can solve for x

$g(x)=-(x+3)(x-7)=0$

$x=-3,x=7$

so, this is TRUE

(e)

we have

$g(x)=x^2+4x-21$

now, we can set it to 0

and then we can solve for x

$g(x)=x^2+4x-21=0$

$(x+7)(x-3)=0$

$x=-7,x=3$

so, this is FALSE

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2 years ago

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What ratios are equivalent to 25:15

Andrei [34K]

25:15,20:10,15:5,10:0

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2 years ago

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