<u>Answer:</u>
Cost of package of paper = 4$
Cost of stapler = 7$
<u>Explanation:</u>
Consider the cost of package of paper = x and that of stapler = y.
Now, we are given that cost of 3 paper packages and 4 staplers = 40$
Hence we get, 3x + 4y = 40 as 1st equation.
we are also given, cost of 5 paper packages and 6 staplers = 62$
Hence, the second equation is 5x + 6y = 62
Now, solving the two equations by method of elimination, we first equate coefficients of any one variable say x by multiplying 1st equation by 5 and second by 3 we get ->
15x + 20y = 200
15x + 18y= 186
Subtracting the two we get y = 7 and substituting this value of y in first equation we get x = 4
which gives the required cost of one paper package = x = 4$
and one stapler = y = 7$
Answer:
(tan(theta)-1)^3
= (tan(theta)-1)(tan(theta)-1)(tan(theta)-1)
= (tan^2(theta)-2tan(theta)+1)(tan(theta)-1)
= tan^3(theta)-2tan^2(theta)+tan(theta)-tan^2(theta)+2tan(theta)-1
= tan^3(theta)-3tan^2(theta)+3tan(theta)-1
Hope this helps :)
The picture is how I solved it and it will be correct
Answer:
26.25 minutes
Step-by-step explanation:
Given that :
Number of pages (p) read by Elias can be modeled by the function ;
p = 45m + 18
Where P = Number of pages ; m = number of minutes
Number of minutes it will take to read a total of 39 pages
p = 4/5m + 18
39 = 4/5m + 18
39 - 18 = 4/5m
21 = 4/5m
4m = 21 * 5
4m = 105
m = 105 / 4
m = 26.25
Answer:
In my opinion math is very important to me and I will be there in a few minutes
