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geniusboy [140]
3 years ago
12

A parabola has a focus of F (8.5,-4) and a directrix of x=9.5.

Mathematics
1 answer:
SVETLANKA909090 [29]3 years ago
7 0

B......is the answer
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If this number is larger than 6, then its square is larger than 36.The number is not larger than 6.therefore Its square is not l
Anit [1.1K]

Answer:

False

Step-by-step explanation:

If this number is larger than 6, then its square is larger than 36.

If x > 6, then x² > 36

The number is not larger than 6.therefore Its square is not larger than 36.

x ≤ 6; therefore, x² ≤ 36

-7 is < 6; however -7² > 36 as -7² = 49

6 0
3 years ago
a 50 ft pole has a support wire that runs from its top to the ground with an angle of depression of 75°. How far from the base o
lukranit [14]
The height of the pole is the vertical leg of the right triangle. The angle of depression is an exterior angle to the triangle at its upper angle. The angle of depression is complementary to the interior angle, so the measure of the interior angle is 15. The base angles are 90 and 75. Use the tangent ratio now, using the base angle of 75 and the height of the pole being 50: tan75=50/x.
Make sure your calculator is in degree mode to do this and get that x = 13.4
4 0
3 years ago
Find the Area of the figure below, composed of a rectangle and a semicircle. The
Keith_Richards [23]

Answer:

60

Step-by-step explanation:

7 0
3 years ago
Student scores on exams given by a certain instructor have mean 74 and standard deviation 14. This instructor is about to give t
Lapatulllka [165]

Answer:

P(\bar X >80)=P(Z>2.143)=1-P(z

Step-by-step explanation:

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

Let X the random variable that represent the Student scores on exams given by a certain instructor, we know that X have the following distribution:

X \sim N(\mu=74, \sigma=14)

The sampling distribution for the sample mean is given by:

\bar X \sim N(\mu,\frac{\sigma}{\sqrt{n}})

The deduction is explained below we have this:

E(\bar X)= E(\sum_{i=1}^{n}\frac{x_i}{n})= \sum_{i=1}^n \frac{E(x_i)}{n}= \frac{n\mu}{n}=\mu

Var(\bar X)=Var(\sum_{i=1}^{n}\frac{x_i}{n})= \frac{1}{n^2}\sum_{i=1}^n Var(x_i)

Since the variance for each individual observation is Var(x_i)=\sigma^2 then:

Var(\bar X)=\frac{n \sigma^2}{n^2}=\frac{\sigma}{n}

And then for this special case:

\bar X \sim N(74,\frac{14}{\sqrt{25}}=2.8)

We are interested on this probability:

P(\bar X >80)

And we have already found the probability distribution for the sample mean on part a. So on this case we can use the z score formula given by:

z=\frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}

Applying this we have the following result:

P(\bar X >80)=P(Z>\frac{80-74}{\frac{14}{\sqrt{25}}})=P(Z>2.143)

And using the normal standard distribution, Excel or a calculator we find this:

P(Z>2.143)=1-P(z

6 0
3 years ago
Jake had 2.95 mL of a liquid. He added more liquid and now has 3.56 mL.
Deffense [45]
3.56 - 2.95 = 0.61

therefore, he added .61 mL of liquid, hope this helped!
4 0
3 years ago
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