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Mnenie [13.5K]
3 years ago
9

PLEASE HELP WITH THIS!! The question is in the picture

Mathematics
1 answer:
bonufazy [111]3 years ago
4 0

x amount they spend each day

4x<1200-585

4x< 615

x< 615/4

if my asnwer helps please mark as brainliest

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A toy maker claims his best product has an average lifespan of exactly 14 years. A skeptical quality control specialist asks for
slamgirl [31]

Answer:

interval = [17.3948 , 20.6052]

Step-by-step explanation:

given,

random sample (n) = 45

average product lifespan = 19 years

standard deviation = 4 years

confidence interval of 99 %  = ?

we know,

t* = qt(1.99/2 + 44 ) = qt(0.995,44)

t* = 2.692

so,

interval

x = 19 \pm t* \times (\dfrac{s}{\sqrt{n}})

x = 19 \pm 2.692 \times (\dfrac{4}{\sqrt{45}})

x = 19 \pm 2.692 \times 0.5963

x = 19 \pm 1.6052

interval = [19 - 1.6052 , 19 + 1.6052]

interval = [17.3948 , 20.6052]

4 0
3 years ago
A fruit-drinking company tester a new flavor. In a taste test, 34% of the people taking part liked the new flavor. If 51 people
almond37 [142]

Answer:

C. 150

Step-by-step explanation:

The number of people who took the test is unknown, so call it x.

34% of x liked the flavor.

51 people liked the flavor.

That means that 34% of x is equal to 51.

34% of x = 51

0.34x = 51

x = 51/0.34

x = 150

Answer: C. 150

4 0
2 years ago
I need help plzz help!!​
Alborosie

Answer:

it's 2 because it's the smallest number

8 0
3 years ago
Whats the rule for the pattern 8,6,9,7,10.....?
Delicious77 [7]

Answer:

subtract 2 and add 3

Step-by-step explanation:

8-2=6

6+3=9

9-2=7

7+3=10

4 0
2 years ago
A study of 25 graduates of 4-year public colleges revealed the mean amount owed by a student in student loans was $55,051. The s
Harman [31]

Answer:

Step 1

The data represent amount.

A 90% confidence interval for the population mean is,

First, compute t-critical value then find confidence interval.

The t critical value for the 90% confidence interval is,

The sample size is small and two-tailed test. Look in the column headed and the row headed in the t distribution table by using degree of freedom is,

The t critical value for the 90% confidence interval is 1.711.

A 90% confidence interval for the population mean is .

Step 2

It is reasonable to conclude that mean of the population is actually $55000 due to a 90% confidence intrerval for population mean is between $52461.23 and $57640.77 does include $55000.

The data represent amount.

A 90% confidence interval for the population mean is,

First, compute t-critical value then find confidence interval.

The t critical value for the 90% confidence interval is,

The sample size is small and two-tailed test. Look in the column headed and the row headed in the t distribution table by using degree of freedom is,

The t critical value for the 90% confidence interval is 1.711.

A 90% confidence interval for the population mean is .

It is reasonable to conclude that mean of the population is actually $55000 due to a 90% confidence intrerval for population mean is between $52461.23 and $57640.77 does include $55000.

5 0
2 years ago
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