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3 years ago

Can someone explain what I am suppose to do please?

Mathematics

1 answer:

finlep [7]3 years ago

3 0

You divide each number by the sscale factor given and total it up and you get the answer

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How do you simplify 3(j-2k)+4 ?

masha68 [24]

Answer: 3j-6k+4

Step-by-step explanation:

First you have to distribute the 3 to the j and the -2k since they are both in the parentheses. So it would look like (3*j) +(-2k*3)+4 and if you simplify that it is 3j-2k+4. After that there are no like terms so that is your answer.

5 0

2 years ago

9 is subtracted from 3 times the sum of 4 and 2

Len [333]

Answer:

Step-by-step explanation:

3 times the sum of 4 and 2 = 3*(4+2)

= 3 * 6

= 18

18 - 9 = 9

8 0

3 years ago

How many solutions does the following system of equations have y=2x+2 & 2y=4x+4

iren [92.7K]

Answer:

y=2x + 2

0= 2x +2

-2x = 2

x= -1

Step-by-step explanation:

2y = 4x +4

2y -4x =4

y-2x =2

-2x +y =2

2x-y=-2

3 0

2 years ago

On a coordinate plane, the segment with endpoints (10, 40) and (70, 120) is

OlgaM077 [116]

Answer:

The length of the resulting segment is 500.

Step-by-step explanation:

Vectorially speaking, the dilation is defined by following operation:

$P'(x,y) = O(x,y) + k\cdot [P(x,y)-O(x,y)]$ (1)

Where:

$O(x,y)$ - Center of dilation.

$P(x,y)$ - Original point.

$k$ - Scale factor.

$P'(x,y)$ - Dilated point.

First, we proceed to determine the coordinates of the dilated segment:

( $P(x,y) = (10, 40)$ , $Q(x,y) = (70, 120)$ , $O(x,y) = (0,0)$ , $k = 5$ )

$P'(x,y) = O(x,y) + k\cdot [P(x,y)-O(x,y)]$

$P(x,y) = (0,0) +5\cdot [(10,40)-(0,0)]$

$P'(x,y) = (50,200)$

$Q'(x,y) = O(x,y) + k\cdot [Q(x,y)-O(x,y)]$

$Q' (x,y) = (0,0) +5\cdot [(70,120)-(0,0)]$

$Q'(x,y) = (350, 600)$

Then, the length of the resulting segment is determined by following Pythagorean identity:

$l_{P'Q'} = \sqrt{(350-50)^{2}+(600-200)^{2}}$

$l_{P'Q'} = 500$

The length of the resulting segment is 500.

3 0

3 years ago

a biker must circle a 12 mile track twice. His average speed must be 60mph. On his first lap he averaged 50 mph. How fast must h

liq [111]

Answer:

75 mph

Step-by-step explanation:

A biker must circle a 12-mile track twice. His average speed must be 60 mph.

So, the average time required to cover the distance is $\frac{2 \times 12}{60} = 0.4$ hours.

Now, on his first lap, he averaged 50 mph.

So, he covered this 12 miles track in $\frac{12}{50} = 0.24$ hours.

Hence, he has to cover the next 12 miles track in (0.4 - 0.24) = 0.16 hours.

Therefore, his average speed in the second round must be $\frac{12}{0.16} = 75$ mph to qualify. (Answer)

8 0

3 years ago