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Natali5045456 [20]
3 years ago
8

Can someone pls help me with this question?

Mathematics
1 answer:
Vadim26 [7]3 years ago
3 0

Answer:

look up desmos graphing cauculator  and type in each function .

Step-by-step explanation:

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How many different pairs of parallel edges are there on a rectangular solid?
Monica [59]

Answer:

18

Step-by-step explanation:

A rectangular prism has four parallel edges along its length, four parallel edges along its width, and four parallel edges along its height.

We want to know how many different pairs of parallel edges there are.  Starting with the length, the number of unique pairs is:

₄C₂ = 6

The same is true for the width and height.  So the total number of different pairs of parallel edges is:

3 × 6 = 18

4 0
3 years ago
The number of shirts Karla owns is in the table.
sineoko [7]

Answer:

A 1:6

Step-by-step explanation:

3:18 simply to 1:6

4 0
3 years ago
Simplify the expression below. (2x^3-12x^2+10x-108)/x-6
ser-zykov [4K]
We have the following expression:
 (2x ^ 3-12x ^ 2 + 10x-108) / x-6
 Dividing the expression between x-6 we have:
 quotient: 2x ^ 2 + 10
 remainder: - 48
 We can check the result then rewriting the expression:
 2x ^ 3-12x ^ 2 + 10x-108
 = (2x ^ 2 + 10) * (x-6) - 48
 = (2x ^ 3 + 10x - 12 x ^ 2 - 60) - 48
 = 2x ^ 3-12x ^ 2 + 10x-108
 Division OK.
 Answer:
 
The result of the division is:
 
quotient: 2x ^ 2 + 10
 
remainder: - 48
5 0
3 years ago
Which missing piece of information would allow the triangles in the figure to be proven congruent by AAS? answer: A) ∠C ≅ ∠L B)
anzhelika [568]

Answer:

B) ∠B ≅ ∠K

Step-by-step explanation:

The Angle-Angle-Side Postulate (AAS) states that if two angles and a non-included side of one triangle are congruent to two angles and the corresponding non-included side of another triangle, then the two triangles are congruent.

Given that ∠A ≅ ∠J and AC ≅ JL, then we need that ∠B ≅ ∠K to satisfy postulate AAS (the two angles are ∠A and ∠B in one triangle and ∠K and ∠J in the other one, and the non-included side is AC in one triangle and JL in the other one).

7 0
3 years ago
Solve the equation x^2 – 16x + 25 = 0 to the nearest tenth.
iren [92.7K]

Answer:

1.8 and 14.3

Step-by-step explanation:

Our equation is a quadratic equation so we will use the dicriminant method

  • Let Δ be our dicriminant
  • a=1
  • b= -16
  • c= 25
  • Δ= (-16)²-4*25*1=156≥0
  • so we have two solutions : x and y
  • x= (16-\sqrt{156})/2= 1.7555≈ 1.8
  • y=(16+\sqrt{156})/2=14.244≈ 14.3

5 0
3 years ago
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