It is given that there are 41 males and 48 females in the small school.
So, the number of ways a male student can be chosen from 41 males is 
Likewise, the number of ways a female student can be chosen from 48 females is 
.
Thus, the total number of ways in which 2-person combinations are possible to represent the student body at the PTSAC meetings will be given by:
<span>given:
bull's eye radius= x
width of surrounding rings=y
solution:
Radius of the circle=x+4y
Area of the outermost ring=Area of the circle-Area of the penultimate ring
=Ď€(x+4y)^2-Ď€(x+3y)^2
=Ď€(x^2+8xy+16y^2-x^2-9y^2-6xy)
=Ď€(2xy+7y^2)
hence the area of the outermost ring in terms of x and y is π(2xy+7y^2).</span>
Given:
Entrance fee per student: $5(29)
Lunch costs: $4(29 + 6)
Bus fees: $25 + 8($2 + $3)
Total cost: 5(29) + 4(35) + 25 + 8(5)
To find:
The equivalent expressions of the total cost that use the properties of operations to simplify the math.
Solution:
We have,
Total cost = 5(29) + 4(35) + 25 + 8(5)
To simply this expression, we need to write 29 and 35 in the expand form or as the sum of their place values because it is easy to multiply a number with multiply of 10 and single digit.
Total cost = 5(20+9) + 4(30+5) + 25 + 40
Therefore, the correct option is B.
Answer:
<h2><u>
<em>Rei 3 years old</em></u></h2><h2><u>
<em>Sasha 11 Years old</em></u></h2>
Step-by-step explanation:
sasha is 8 years than ei. the sum of their ages is 14. find the ages os sasha and rei
(14 - 8) : 2 = 3 (Rei)
8 + 3 = 11 (Sasha)
------------------
11 + 3 = 14
the answer is good
1. To answer the questions shown in the figure atttached, it is important to remember that the irrational number e is aldo called "Euler's number" and you can find it in many exercises in mathematics.
2. Then, the irrational number e is:
e=<span>2.71828
</span>
3. When you rounded, you have:
e=<span>2.718
</span>
4. Therefore, as you can see, the the correct answer for the exercise above is the option c, which is: c. 2.718
