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ArbitrLikvidat [17]
3 years ago
10

5. How can a budget prepare you to become financially secure?

Computers and Technology
2 answers:
Nady [450]3 years ago
8 0

Answer:

Because you have a certain amount of money you’ll be able to spend for a certain period and helps you not go over your budget. In other words, it helps you keep track of your money so that you don’t waste more money than you are supposed to.

Explanation:

Strike441 [17]3 years ago
5 0

Answer: A budget can prepare someone to have their expenses in order and to ensure their own financial security by allowing for a clear cut route to pay off any debts or expenses whilst also leaving room for what can be spent on wants as opposed to needs. Without a budget, people would be aimlessly paying for things without knowing what they can or cannot spend frivolously.

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Refer below.

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How to make a Tip Calculator in code?
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Advocard [28]

Answer:

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Answer:

#include "Lab11_jlilly3_204.h"

#include <stdio.h>

#include <stdlib.h>

#define BYTETOBINARYPATTERN "%d%d%d%d%d%d%d%d"

#define BYTETOBINARY(byte) \

(byte & 0x80 ? 1 : 0), \

(byte & 0x40 ? 1 : 0), \

(byte & 0x20 ? 1 : 0), \

(byte & 0x10 ? 1 : 0), \

(byte & 0x08 ? 1 : 0), \

(byte & 0x04 ? 1 : 0), \

(byte & 0x02 ? 1 : 0), \

(byte & 0x01 ? 1 : 0)

#define PRINTBIN(x) printf(BYTETOBINARYPATTERN, BYTETOBINARY(x));

//! Set the least significant bit for all values in an array to the coorrisponding bit pos. in b_o

void setlsbs(unsigned char* p, unsigned char b_0)

{

int i;

for (i = 0; i < 8; i++)

{

int x = b_0 & 1;

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p[i] |= x;

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else

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p[i] &= ~1;

}

// shift our bit to the right to get the next value in the bit

b_0 = b_0 >> 1;

}

}

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unsigned char getlsbs(unsigned char *p)

{

int i;

unsigned char c = 0;

for (i = 0; i < 8; i++)

{

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{

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c |= 1 << i;

}

}

return c;

}

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void print_decimal(unsigned char* p)

{

int k;

for (k = 0; k < 8; k++)

{

printf("Num at %d: %d\n", k, p[k]);

}

}

//! Print a given array in in bianary representation

void print_bin(unsigned char* p)

{

int c;

for (c = 0; c < 8; c++)

{

printf("Num at %d ", c);

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printf("\n");

}

}

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velikii [3]

Answer:

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Explanation:

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