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myrzilka [38]
3 years ago
9

6 4. 2 74-22 2 4- 6 Slope

Mathematics
1 answer:
mamaluj [8]3 years ago
4 0
6+6+4+4-2+2+74+22 =120
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8° below zero in the winter ​
Sergio039 [100]

Answer:

negative

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
PLEASE HELP ASAP!!!!!
attashe74 [19]
For this case what we must do is use the law of cosines.
 We then have the following equation:
 c ^ 2 = a ^ 2 + b ^ 2 - 2 * a * b * cos (x)

 Where,
 a, b: sides of the triangle
 x: angle between sides a and b.
 Substituting values we have:
 c^2 = 90^2 + 75^2 - 2*90*75*cos(85)

 Clearing the value of c we have:
 c =  \sqrt{ 90^2 + 75^2 - 2*90*75*cos(85)}
 Answer:
 
An expression that is equivalent to how many feet the oak trees are from each other is:
 
c = \sqrt{ 90^2 + 75^2 - 2*90*75*cos(85)}
7 0
3 years ago
20 points answer right uestion 1(Multiple Choice Worth 4 points)
suter [353]

Answer:

two and one fifth

Step-by-step explanation:

8 0
3 years ago
25 (a square) - 4 (b square) + 28bc - 49 (c square)
LUCKY_DIMON [66]

Answer:

(5a - [2b - 7c]) and (5a + [2b + 7c])

Step-by-step explanation:

Factor 25a^2 - 4b^2 + 28bc - 49c^2.

Note that - 4b^2 + 28bc - 49c^2 involves the variables b and c, whereas 25a^2 has only one variable.  Thus, try to rewrite - 4b^2 + 28bc - 49c^2 as the square of a binomial:

- 4b^2 + 28bc - 49c^2 = -(4b^2 - 28bc + 49c^2), or

                                        -(2b - 7c)^2.

Thus, the original  25a^2 - 4b^2 + 28bc - 49c^2  looks like:

                               [5a]^2 - [2b - 7c]^2

Recall that a^2 - b^2 is a special product, the product of (a + b) and (a - b).  Applying this pattern to the problem at hand, we conclude:

Thus,   [5a]^2 - [2b - 7c]^2 has the factors (5a - [2b - 7c]) and (5a + [2b + 7c])

8 0
3 years ago
On Monday, Sarah has to meet her friend at the park after school The distance from her house to school is 2x+5 The distance from
DanielleElmas [232]

Answer:

8x + 4 - z

Step-by-step explanation:

Given the following :

The distance from her house to school is 2x+5 The distance from the school to the park is z If the total distance she was that day is 10x +9 how far is it from the park back to her

Distance from house to school = 2x + 5

Distance from school to park = z

Total distance covered = 10x + 9

Distance from park to house =?

Total distance = (distance from house to school + distance from school to park + distance from park to house)

Let p = distance from park to house

10x + 9 = (2x + 5 + z + p)

10x + 9 - 2x - 5 - z = p

8x + 4 - z

6 0
3 years ago
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