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dolphi86 [110]
3 years ago
15

A small company has an advertising budget of $15,000.The company plans to produce and air a television commercial. It will cost

$500 to produce the commercial and an additional $50 each time the commercial is aired. How many days can the company afford to run the commercial if it is aired once a day?
Mathematics
2 answers:
Nikolay [14]3 years ago
5 0

Answer:

290 days max

I hope this helps ;-; i tried and i'm kinda running out of time, Your Welcome!

Nana76 [90]3 years ago
4 0

Answer:

290 days

Step-by-step explanation:

We know the starting cost is $500. Suppose the commercial is aired x times. That means the cost will be a total of 50x.

Adding that to 500, we get a total of 50x + 500.

The company's budget is only $15,000, so we set this equal to 50x + 500 to find x:

50x + 500 = 15,000

50x = 14,500

x = 290

The answer is 290 days.

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Answer:

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Step-by-step explanation:

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6 0
3 years ago
A museum requires a minimum number of chaperones proportional to the number of students on a field trip. The museum requires a m
Stells [14]

Answer: See explanation

Step-by-step explanation:

Here is the complete question:

A museum requires a minimum number of chaperones proportional to the number of students on a field trip. The museum requires a minimum of 3 chaperones for a field trip with 24 students. Which of the following could be combinations of values for the students and the minimum number of chaperones the museum requires? Choose 2 answers.

A. Students: 72

Minimum of chaperones: 9

B. Students: 16

Minimum of chaperones: 2

C. Students: 60

Minimum of chaperones: 6

D. Students: 45

Minimum of chaperones: 5

E. Students: 40

Minimum of chaperones: 8

Since the museum requires a minimum of 3 chaperones for a field trip with 24 students. This means that there will be 24/3 = 8 students per chaperone.

We then divide the number of students given in the question by the number of chaperone to know our answers. This. Will be:

Students: 72

Minimum of chaperones: 9

This will be: 72/9 = 8

Therefore, this is correct.

B. Students: 16

Minimum of chaperones: 2

This will be: 16/2 = 8

This is correct

C. Students: 60

Minimum of chaperones: 6

This will be: = 60/6 = 10.

Therefore, this is wrong

D. Students: 45

Minimum of chaperones: 5

This will be 45/5 = 9

Therefore, this is wrong.

E. Students: 40

Minimum of chaperones: 8

This will be: 40/5 = 8.

Therefore, this is wrong.

Therefore, options A and B are correct.

3 0
3 years ago
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33.75 = 2*1.5*x
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3 years ago
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alexandr1967 [171]
So 45% OF 40 is 
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18 is 18% of what number?
18 = 18% * x
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