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german
3 years ago
11

A team of explorers going to South Pole expect to travel 1014.15km in total the team expect their average sped for expidition n

to be 19.12km for expedition will travel 12hours a day estimate how many days the team will take to complete expidition
Mathematics
1 answer:
Paul [167]3 years ago
4 0

It will take them about 26 days to complete the expedition

<h2>Proportion and distance</h2>

According to the information, the team of explorers is to travel 19.12km in 12 hours

  • 19.12 km  = 12 hours

If they are expected to travel 1014.15km in total, the total time taken is given as:

1014.15km = x

Take their proportions:

\frac{19.12}{1014.15} = \frac{12}{x} \\&#10;19.12x = 12,169.8\\&#10;x = 636.495hours

Convert the time taken to days;

x =\frac{636.495}{24}\\&#10; x \approx 26.5 days

This shows that it will take them about 26 days to complete the expidition.

Learn more on proportion here: brainly.com/question/19994681

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Dmitriy789 [7]

Suppose

S=50+51+52+\cdots+100+101

At the same time, we can write

S^*=101+100+99+\cdots+51+50

Note that S=S^* (just reverse the sum). Let's pair the first terms of S and S^*, and the second, and the third, and so on:

S+S^*=(50+101)+(51+100)+(52+99)+\cdots+(100+51)+(101+50)

Now, each grouped term in the sum on the right side adds to 151. There are 52 grouped terms on that same side (because there are 50 numbers in the range of integers 51-100, plus 50 and 101), which menas

S+S^*=52\cdot151

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3 years ago
A bus as speed of 20m/s begin to slow at constant acceleration of 8.00m/s2 along a straight line find the average speed for the
MrRissso [65]

Answer:

-20 m/s.

Step-by-step explanation:

The computation of the average speed is shown below:

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time of motion, t = 5 s

Now The final velocity of the bus is  

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PolarNik [594]

Answer:

<em />8>3<em />

Step-by-step explanation:

STEP 1: <em>Rewrite so   n is on the left side of the inequality.</em>

6n+8-2n>4n+3

STEP 2: <em>Subtract  2 n  from  6 n .</em>

4n+8>4n+3

STEP 3: <em>Move all terms containing  n  to the left side of the inequality.</em>

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3 years ago
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Alchen [17]

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