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o-na [289]
3 years ago
5

Please help. will mark brainliest if its right.180-x=3(90-x)

Mathematics
1 answer:
DerKrebs [107]3 years ago
4 0
<h2>hope it helps you please mark me as brainliest </h2>

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On a coordinate plane, triangle A B C is shifted 4 units to the right and 2 units up to form triangle A prime B prime C prime. I
zheka24 [161]

Answer:

(x, y) ⟶ (x + 4, y + 2)  

Step-by-step explanation:

If you shift a point four units to the right, x ⟶ x + 4.

If you shift it up two units, y ⟶ y + 2.

If you combine the two shifts into one transformation, the rule becomes

(x, y) ⟶ (x + 4, y + 2)

3 0
3 years ago
Plz help first right gets brainly
Anestetic [448]
A. Is not linear because is has no y
How this helped ya out! :D
6 0
3 years ago
Read 2 more answers
Suppose an isosceles triangle ABC has A= pi/6 and b=5=c. What is the length of a^2.
ioda
5^2(2-sqrt3) is the answer here is the link to how to do it https://socratic.org/questions/suppose-an-isosceles-triangle-abc-has-a-30-and-b-c-5-what-is-the-leng...
5 0
3 years ago
A rectangle has vertices E(-4, 8), F(2, 8), G(2, -2) and H(-4, -2). The rectangle is dilated with the origin as the center of di
Marizza181 [45]

Answer:

The dilation on any point of the rectangle is P'(x,y) = \frac{5}{2}\cdot P(x,y).

Step-by-step explanation:

From Linear Algebra, we define the dilation of a point by means of the following definition:

G'(x,y) = O(x,y) +k\cdot [G(x,y)-O(x,y)] (1)

Where:

G(x,y) - Coordinates of the point G, dimensionless.

O(x,y) - Center of dilation, dimensionless.

k - Scale factor, dimensionless.

G'(x,y) - Coordinates of the point G', dimensionless.

If we know that O(x,y) = (0,0), G(x,y) =(2,-2) and G'(x,y) =(5,-5), then scale factor is:

(5,-5) = (0,0) +k\cdot [(2,-2)-(0,0)]

(5,-5) = (2\cdot k, -2\cdot k)

k = \frac{5}{2}

The dilation on any point of the rectangle is:

P'(x,y) = (0,0) + \frac{5}{2}\cdot [P(x,y)-(0,0)]

P'(x,y) = \frac{5}{2}\cdot P(x,y) (2)

The dilation on any point of the rectangle is P'(x,y) = \frac{5}{2}\cdot P(x,y).

5 0
3 years ago
Which value of $y$ makes the equation $3y+8=7y+11$ true?
valentinak56 [21]

value of y which satisfies equation 3y+8=7y+11 is  y= \frac{-3}{4} .

<u>Step-by-step explanation:</u>

We have , 3y+8=7y+11 . We need to find which value of y satisfies this equation  3y+8=7y+11 :

3y+8=7y+11

⇒ 3y+8=7y+11

⇒ (3y+8)-3y=(7y+11)-3y

⇒ 8=4y+11

⇒ 4y+11 = 8

⇒ (4y+11)-11 = 8-11

⇒ 4y= -3

⇒ \frac{4}{4}y= \frac{-3}{4}

⇒ y= \frac{-3}{4}

Therefore, value of y which satisfies equation 3y+8=7y+11 is  y= \frac{-3}{4} .

8 0
3 years ago
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