The function has a y-intercept at (0, 2). Then the correct options are A, B, and E.
The complete question is attached below.
<h3>What is the maximum and minimum value of the function?</h3>The condition for the maximum will be
f"(x) < 0
The condition for the minimum will be
f"(x) > 0
Consider the inverse function.
f⁻¹(x) = -√(x - 2)
Then the conclusion of the function f(x) = x² + 2 will be
Differentiate the function, then we have
f ' (x) = 2x
Again differentiate, then we have
f" (x) = 2
f" (x) > 0
Then the function has a minimum value at (0, 2)
The function has a y-intercept at (0, 2)
Then the correct options are A, B, and E.
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