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3 years ago

12

Blank times 6/12 = 1/10

1 answer:

Goryan [66]3 years ago

8 0

2/10 is the answer.

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Move the slider on the graph on the right to graph each function:

DedPeter [7]

Answer:

The domain is $x\geq 7$

The range is $y\geq 1$

Step-by-step explanation:

we have

$y=\sqrt{x-7} +1$

<em>Find the domain</em>

Remember that

The domain of a function is the set of all possible values of x

we know that the radicand of the function must be greater than or equal to zero

so

$x-7\geq 0$

solve for x

$x\geq 7$

therefore

The domain is $x\geq 7$

<em>Find the range</em>

Remember that

The range of a function is the complete set of all possible resulting values of y, after we have substituted the domain.

For x=7

The value of y is equal to

$y=\sqrt{7-7} +1=1$

so

The solution for y is the interval [1,∞)

therefore

The range is $y\geq 1$

6 0

2 years ago

Read 2 more answers

PLEASEEEE HELP ASAP!!!

lidiya [134]

Your answer is point g and h

6 0

3 years ago

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A six-sided number cube is rolled twice.

kondor19780726 [428]

The probability is 1/6, 16%, or 0.16

5 0

3 years ago

Simplify the number into simplest radical form. Use the factor tree to help determine the factors. StartRoot 96 Endroot StartRoo

NikAS [45]

Answer:

$[tex]4608\sqrt{3}$ [/tex]

Step-by-step explanation:

1. $\sqrt{96} *\sqrt{6}* 2*\sqrt{6}*4 *\sqrt{6} *4*\sqrt{3}$

2. $\sqrt{2^{5} *3} \sqrt{6} *2\sqrt{6}*4\sqrt{6}*4\sqrt{3}$ <em>factoring 96</em>

<em>since $\sqrt{2^{5}*3 } = \sqrt{2^{5} } \sqrt{3}$ </em>

3. $\sqrt{2^{5} } \sqrt{3}\sqrt{6} *2\sqrt{6}*4\sqrt{6}*4\sqrt{3}$

<em>using exponent rule - $(a^{b}) ^{c} = a^{bc}$ </em>

<em> $\sqrt{2^{5} } = 2^{5/2}$ </em>

4. $2^{5/2}\sqrt{3}\sqrt{2*3} *2\sqrt{6}*4\sqrt{6}*4\sqrt{3}$

<em>doing some simple simplification and $4=2^{2}$ and 6=2*3</em>

5. $2^{5/2} \sqrt{3} \sqrt{2} \sqrt{3} *2\sqrt{2} \sqrt{3} *2^{2}\sqrt{2} \sqrt{3}*4\sqrt{3}$

<em>collecting the roots on one side and applying exponent rule</em>

6. $\sqrt{3} \sqrt{3}\sqrt{3} \sqrt{3}\sqrt{2} \sqrt{2}\sqrt{2} *2^{5/2+1+2+2} \sqrt{3}$

<em>Applying exponents rule on all $\sqrt{3}$ and $\sqrt{2}$ </em>

<em>7. $2^{1/2+1/2+1/2} *2^{5/2+1+2+2}*3^{1/2+1/2+1/2+1/2+1/2}$ </em>

<em>combining all powers of 2</em>

8. $2^{1/2+1/2+1/2+5/2+1+2+2}*3^{1/2+1/2+1/2+1/2+1/2}$

<em>Simplifying</em>

9. $2^{9} *3^{2}\sqrt{3}$

10. $512*9\sqrt{3}$

11. $4608\sqrt{3}$

3 0

3 years ago

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I need help I need to be tutored for middle school I need to be a straight A student

Yuri [45]

Answer:

ok

Step-by-step explanation:

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3 years ago