The slope of the green line if the lines are perpendicular is -1/4
<h3>Perpendicular lines</h3>
For two lines two be perpendicular, the product of their slope must be -1. Let the slope of the red and green line be m1 and m2.
Given the following
Slope of red line = 4
According the definition
4m2 = -1
m2 = -1/4
Hence the slope of the green line if the lines are perpendicular is -1/4
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Answer:
2 real solutions
Step-by-step explanation:
Get all the terms to one side
10n^2 = 10 - 8n
10n^2 +8n -10 =0
ax^2 +bx+c =0
The discriminant is
b^2 -4ac
8^2 - 4(10)(-10)
64 +400
464
If the discriminant is greater than 0 we have 2 real solutions
First isolate the "y" in the equation.
2y - x = -12 Add x on both sides
2y - x + x = -12 + x
2y = -12 + x Divide 2 on both sides to get "y" by itself
Your slope is 
.
For the equation of the line to be parallel to the given equation, the slopes have to be the same. So the parallel line's slope is also
y = mx + b
To find "b", you plug in the point (18,2) into the equation
2 = 9 + b Subtract 9 on both sides
2 - 9 = 9 - 9 + b
-7 = b
Your equation is:
