How fast the volume of the sphere is changing when the surface area is 10 square centimeters is it is increasing at a rate of 30 cm³/s.
To solve the question, we need to know the volume of a sphere
<h3>
Volume of a sphere</h3>
The volume of a sphere V = 4πr³/3 where r = radius of sphere.
<h3>How fast the volume of the sphere is changing</h3>
To find the how fast the volume of the sphere is changing, we find rate of change of volume of the sphere. Thus, we differentiate its volume with respect to time.
So, dV/dt = d(4πr³/3)/dt
= d(4πr³/3)/dr × dr/dt
= 4πr²dr/dt where
- dr/dt = rate of change of radius of sphere and
- 4πr² = surface area of sphere
Given that
- dr/dt = + 3 cm/s (positive since it is increasing) and
- 4πr² = surface area of sphere = 10 cm²,
Substituting the values of the variables into the equation, we have
dV/dt = 4πr²dr/dt
dV/dt = 10 cm² × 3 cm/s
dV/dt = 30 cm³/s
So, how fast the volume of the sphere is changing when the surface area is 10 square centimeters is it is increasing at a rate of 30 cm³/s.
Learn more about how fast volume of sphere is changing here:
brainly.com/question/25814490
Answer:
The correct answer to the question: Suppose there is a mutation in a laminin-binding integrin gene that causes a loss of function in the cytoplasmic domains of the integrin. Which one of the following would you expect to observe as a result of this mutation?, would be, C) The strength of tissues would be decreased because the integrin could no longer associate with intermediate filaments in hemidesmosomes.
Answer:
25, 36, 49
Step-by-step explanation:
I just listed them down since there aren't many.
1×1=2 (Smaller than 20)
2×2=4 (Smaller than 20)
3×3=9 (Smaller than 20)
4×4=16 (Smaller than 20)
5×5=25
6×6=36
7×7=49
8×8=64 (Bigger than 50)
The third one. I need to add extra characters though so shdmsns
Quick! Quick! Err...
3 * 5/8 would be
15/8 and
2* 7/8 would be
14/8 so
Your answer is 1/8 :)
<em>Please don't forget to choose which answer is Brainliest!</em>
