Answer:
True they do. mark brainliest.!!!!! please
Explanation:
// Making a function that will take a integer as argument and return print the code
void Print(int statuscode){
// starting the switch statement on the interger sent
switch(statuscode)
case 200: // for case 200
cout << "Ok,Fullfilled"<< endl;
case 403: // for case 403
cout << "Forbidden" << endl;
case 404: // for case 404
cout << "Not Found" <<endl;
case 500: // for case 500
cout << "Server Error "<< endl;
default: // default case
cout << " Wrong code"<<endl;
}
Answer:
There is no value of the number variable, for which the loop can be true in any iteration.
Explanation:
- The above loop states the condition that the value should be less than 100 and greater than 500. It is because the loop holds the and condition which gives the true if both conditions will be true.
- The first condition of the while loop states that the value of the number variable is less than the 100.
- The second condition of the while loop state that the value of the number variable is greater than the 500.
- The and condition of the while loop will true if both conditions will true.
- But there is no number which is less than 100 and greater than 500.
- So no number can satisfy the while condition to be true.
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