Write down the exact value of: a) cos 60° b) sin 0° c) tan 45°

40 POINTS!!!! Which sequence of transformations will result in an image that maps onto itself?

White raven [17]

Answer:

Option C.

Step-by-step explanation:

Let a point (x, y) has a sequence of transformations,

Option A).

Reflects across x-axis then the coordinates will be,

(x, y) → (x, -y)

Then reflects across the y-axis,

(x, -y) → (-x, -y)

Image (x, y) gets changed to (-x, -y) therefore, point (x, y) doesn't map onto itself.

Option B).

(x, y) rotate 90° counter clockwise about the origin.

(x, y) → (-y, x)

Then reflect across x-axis,

(-y, x) → (y, x)

Since coordinates of the image and the actual are not same therefore, image doesn't map itself.

Option C).

(x, y) when reflected across x-axis,

(x, y) → (x, -y)

Then reflected over the x-axis,

(x, -y) → (x, y)

In this option point (x, y) maps onto itself after these transformations.

Option D).

(x, y) rotated 90°counterclockwise about the origin

(x, y) → (-y, x)

Then translated up by 2 units.

(-y, x) → (-y, x+2)

Therefore, (x, y) gets changed after these transformations and doesn't maps itself.

Option (C) will be the answer.

7 0

3 years ago

<img src="https://tex.z-dn.net/?f=F%28x%29%20%3D%20%5Cfrac%7Bx%5E%7B3-8%7D%20%7D%7Bx%5E%7B2%7D%20-6x%2B8%7D" id="TexFormula1" ti

Firlakuza [10]

Answer:

Domain: All the real values except x = 2 and x = 4: R - {2, 4}
Holes: x = 2
VA, vertical asymptores: x = 4
HA: horizontal asymptotes: there are not horizontal asymptotes
OA: oblique asymptotes: x + 6 [note that OH does not stand for any known feature, and so it is understood that it was intended to write OA]
Roots: x = 2
Y-intercept: -1

Step-by-step explanation:

1. Given:

$f(x)=\frac{x^3-8}{x^2-6x+8}$

Note that the number 8 in the numerator is not part of the power.

Type of function: rational function

2. Domain: is the set of x-values for which the function is defined.

The given function is defined for all x except those for which the denominator equals 0.

Denominator: x² -6x + 8 = 0

Solve for x:

Factor. (x - 4 )(x - 2) = 0

Zero product property: (x - 4) = 0 or (x - 2) = 0

x - 4 = 0 ⇒ x = 4

x - 2 = 0 ⇒ x = 2

Domain:

All the real values except x = 2 and x = 4: x ∈ R / x ≠ 2 and x ≠ 4.

3. Holes:

The holes on the graph of a rational function are at those x-values for which both the numerator and denominator are zero.

Find the values for which the numerator is zero:

Numerator: x³ - 8 = 0

Factor using difference of cubes property:

a³ - b³ = (a - b)(a² + ab + b²)

x³ - 8 = (x - 2)(x² + 2x + 4) = 0

Zero product property: (x - 2)(x² + 2x + 4) = 0

x - 2 = 0 ⇒ x = 2

x² + 2x + 4 = 0 (this has not real solution)

The values for which the denominator is zero were determined above: x = 2 and x = 4.

Conclusion: for x = 2 both numerator and denominator equal 0, so this is a hole.

4. VA: Vertical asymptotes.

The vertical asymptotes on the graph of a rational function are the vertical lines for which only the denominator (and not the numerator) equals zero.

In the previous part it was determined that happens when x = 4.

5. HA: Horizontal asymptotes.

In rational functions, if the numerator is a higher degree polynomial than the denominator, there is no horizontal asymptote.

6. OA: oblique asymptotes

Find the quotient and the remainder.

x + 6

_______________

x² - 6x + 8 ) x³ + 0x² + 0x - 8

- x³ + 6x² - 8x

___________

6 x² - 8x - 8

- 6x² + 36x - 48

_____________

28x - 56

Result: (x + 6) + (28x - 56) / (x² - 6x + 8)

Find limit x → ∞

$\lim_{x \to \infty}(x + 6) + \frac{28x-56}{x^2-6x+8}=x+6$

7. Roots:

Roots are the values for which f(x) = 0.

That happens when the numerator equals 0, and the denominator is not 0.

As determined earlier: x³ - 8 = 0 ⇒ x = 2.

8. Y-Intercept

The y-intercepts of any function are the y-values when x = 0

Substitute x = 0 into the function:

$f(x)=\frac{x^3-8}{x^2-6x+8}=\frac{0^3-8}{0^2-6(0)+8}}=\frac{-8}{8} =-1$

3 0

3 years ago

What is the answer to this question?

Anni [7]

Three is also 44 and two and four are 136

7 0

3 years ago

Please solve this Solve by completing the square. 4x2+8x−3=0

Greeley [361]

Step-by-step explanation:

4x2+8x−3=0

For this equation: a=4, b=8, c=-3

4x2+8x+−3=0

Step 1: Use quadratic formula with a=4, b=8, c=-3.

x=

−b±√b2−4ac

2a

x= −(8)±√(8)2−4(4)(−3)

2(4)

x= −8±√112

8 x=−1+

1 2 √7 or x=−1+

−1 2 √7

Answer: x=−1+

1 2√7 or x=−1+

−1 2 √7

7 0

2 years ago

Simplify <img src="https://tex.z-dn.net/?f=%20%5Csqrt%7B%20%5Cfrac%7B3%7D%7B8%7D%20%7D%20" id="TexFormula1" title=" \sqrt{ \f

Pie

Answer:

B (√6)/4

Step-by-step explanation:

The smallest multiplier that will make the denominator of the fraction into a perfect square is 2, so you have ...

$\displaystyle\sqrt{\frac{3}{8}}=\sqrt{\frac{3\cdot 2}{8\cdot 2}}\\\\=\sqrt{\frac{6}{16}}=\frac{\sqrt{6}}{\sqrt{16}}\\\\=\frac{\sqrt{6}}{4}$

_____

Answer choice D is also a correct rationalization of the denominator, but is not simplified as far as it can be. √24 = 2√6, so a factor of 2 can be cancelled from numerator and denominator, giving answer choice B.

3 0

3 years ago