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Neko [114]
2 years ago
10

Pls help with number 3

Mathematics
2 answers:
Arturiano [62]2 years ago
5 0

Answer:

about 17

Step-by-step explanation:

side 1 =4

side 2=4

side 3=4

one of the slanted lines is about equal to 2 and the other is also about 2

but i rounded it to 17 because a slanted line is longer than one that is straight across

ddd [48]2 years ago
5 0
Thank you so much took test it was correct thank you
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The sum of a number times 8 and 21 is less than -16.
vodka [1.7K]

Hello.

First of all, let the number be t.

8 times t can be written like this:

\mathrm{8t}

Notice that the number is before the variable and the times sign (×) is not there.

We can write it as 8×t, but we usually write it as 8t.

The sum of means we add:

8t+21

Now, "less than" is "<" :

\mathrm{8t+21 < -16}

Therefore, the answer is

\mathrm{8t+21 < -16}

I hope it helps.

Have a nice day.

\boxed{imperturbability}

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2 years ago
if you took a loan of fifteen million dollars from the bank and the loan is to be repaid in ten years at a simple interest of 5%
Vikki [24]

$750000 for all 10 years and $375000 for just ten years

7 0
3 years ago
28. Rewrite the Scientific Notation into expanded form (normal number).<br> 8.675309 x 10
Aleks [24]
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3 0
3 years ago
2^2/5+ 3^1/10 <br> HELP ASAP
gizmo_the_mogwai [7]

Answer:

\sqrt[5]{4}  + \sqrt[10]{3}

Step-by-step explanation:

We sure can write 2^2/5+ 3^1/10 as 2^{\frac{2}{5} } + 3^{\frac{1}{10} }

// use the a^{\frac{m}{n} }  =\sqrt[n]{a^{m} } to transform the expression

Convert 2^{\frac{2}{5} } to \sqrt[5]{2^{2} } = \sqrt[5]{4}                        (here a = 2, n = 5, m = 2)

Then convert  3^{\frac{1}{10} } to \sqrt[10]{3^{1} } = \sqrt[10]{3}             (here a = 3, n = 10, m = 1)

Now we get  2^{\frac{2}{5} } + 3^{\frac{1}{10} } = \sqrt[5]{4}  + \sqrt[10]{3} . This is the simplified form, which is the answer.

6 0
3 years ago
I dont Understand this so can anyone help me please!! Thank you
storchak [24]
Youre correect answer is 70
3 0
4 years ago
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