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denpristay [2]
3 years ago
7

Please help! Question and answers are on the image

SAT
1 answer:
Maslowich3 years ago
7 0

Answer:

the third one............

Explanation:

c) the third one

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In two common species of flowers, a and b, the proportions of flowers that are blue are pa and pb , respectively. Suppose that i
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The mean of the sampling distribution is {p_{a}}-p__b}

The mean of a sampling distribution is the population mean from which values are sampled. For a population of mean μ, the mean of the sampling distribution is \mathbf{ \mu_x}

∴

\mathbf{\mu_x = \mu}

From the parameters given:

  • Suppose that independent random samples of 50 species-a flowers
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where;

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  • \mathbf{\hat p_b} = sample proprotion of blue specie-b

The mean of the sampling distribution of \mathbf{\hat p_a -\hat p_b} is {p_{a}}-p__b}

Learn more about mean of the sampling distribution here:

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