Plot the graph of the function
on the coordinate plane (see attached diagram). This graph has three points of intersection with x-axis. This means that the equation
has three real solutions.
The given equation is the equation of 5th power, therefore, it has 5 roots. If it has three real roots, then the remaining two roots are complex.
Answer: 2 complex roots.
Answer:
It isn’t true that corresponding cross-sections have the same area.
Step-by-step explanation:
I got it off of khan academy.
Answer:
- m∠1=m∠4=m∠5=m∠8=67°;
- m∠2=m∠3=m∠6=m∠7=113°.
Step-by-step explanation:
Consider two parallel lines a and b with transversal m. These lines form 8 angles.
Note that
Since the difference of two angles is 46°, then these angles should be, for example, ∠1 and ∠2. These angles are supplementary, then
m∠1+m∠2=180°.
Solve the system of two equations:
![\left\{\begin{array}{l}m\angle 1+m\angle 2=180^{\circ}\\m\angle 2-m\angle 1=46^{\circ}\end{array}\right.\Rightarrow \left\{\begin{array}{l}2m\angle 2=226^{\circ}\\2m\angle 1=134^{\circ}\end{array}\right.\Rightarrow \left\{\begin{array}{l}m\angle 2=113^{\circ}\\m\angle 1=67^{\circ}\end{array}\right..](https://tex.z-dn.net/?f=%5Cleft%5C%7B%5Cbegin%7Barray%7D%7Bl%7Dm%5Cangle%201%2Bm%5Cangle%202%3D180%5E%7B%5Ccirc%7D%5C%5Cm%5Cangle%202-m%5Cangle%201%3D46%5E%7B%5Ccirc%7D%5Cend%7Barray%7D%5Cright.%5CRightarrow%20%5Cleft%5C%7B%5Cbegin%7Barray%7D%7Bl%7D2m%5Cangle%202%3D226%5E%7B%5Ccirc%7D%5C%5C2m%5Cangle%201%3D134%5E%7B%5Ccirc%7D%5Cend%7Barray%7D%5Cright.%5CRightarrow%20%5Cleft%5C%7B%5Cbegin%7Barray%7D%7Bl%7Dm%5Cangle%202%3D113%5E%7B%5Ccirc%7D%5C%5Cm%5Cangle%201%3D67%5E%7B%5Ccirc%7D%5Cend%7Barray%7D%5Cright..)
Then
- m∠1=m∠4=m∠5=m∠8=67°;
- m∠2=m∠3=m∠6=m∠7=113°.