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3 years ago

Find the y-value given the x-value: y = x^2; x = -9 y = x?; x = -9

Mathematics

1 answer:

Delvig [45]3 years ago

5 0

Answer:

For the y= x^2 x = -9 y = 81

Step-by-step explanation:

x^2

x=-9

-9^2

-9 * -9

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An H0-scale model railroad engine is 9 inches long. The H0 scale is 87 feet to 1 foot. How long is a real engine?

Semmy [17]

The real engine is 65.25 feet long

<h3>How to determine the length?</h3>

The scale is given as:

Scale = 87 feet to 1 foot

The scale length is given as

Scale length = 9 inches

Convert inches to feet

Scale length = 9/12 feet

The actual length is then calculated as:

Actual = 87 * 9/12 feet

Evaluate

Actual = 65.25 feet

Hence, the real engine is 65.25 feet long

Read more about scale ratios at:

brainly.com/question/16192120

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2 years ago

PLEASE HELP!! WILL GIVE BRAINLIEST TO RIGHT ANSWER.

Ludmilka [50]

Answer:

$f(x)=\sqrt{8-7}=\sqrt{1}=1$

Step-by-step explanation:

$f(x)=\sqrt{x-7}\\\\f(x)=\sqrt{8-7}=\sqrt{1}=1$

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3 years ago

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Find the product.<br> (s + t)(5s – 7t)

joja [24]

Answer:

5s^2 - 30st - 7t^2

Step-by-step explanation:

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3 years ago

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Identify the solution to the system of equations

Lina20 [59]

Answer:

(-2, -1).

Step-by-step explanation:

When trying to find the solution to a system of equations <u>graphically</u>, all you need to do is find the <u>point of intersection</u> between the two equations.

In the graph pictured, we can see that the two equations <u>intersect</u> at (-2,-1).

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3 years ago

Find the general solution of the nonhomogeneous differential equation x^2y''-2y=3(x^2) -1, (x>0).

Ira Lisetskai [31]

Answer:

G.S= $C_1\frac{1}{x}+C_2x^2+x^2logx+\frac{1}{2}$

Step-by-step explanation:

We are given that non-homogeneous differential equation

$x^2y''-2y=3(x^2)-1$

It is Cauchy Euler equation

Substitute x=e^t x>0

Auxillary equation

$D'(D'-1)-2=0$

$D'^2-D'-2=0$

$(D'-2)(D'+1)=0$

$D'-2=0 \implies D'=2$

$D'+1=0\implies D'=-1$

Complementary solution

$y=C_1e^{-t}+C_2e^{2t}$

$y=C_1\frac{1}{x}+C_2x^2$

Particular solution

$y_p=\frac{3e^{2t}}{D'^2-D'-2}-\frac{e^{0t}}{D'^2-D'-2}$

$y_p=te^{2t}+\frac{1}{2}=x^2logx+\frac{1}{2}$

G.S= $C_1\frac{1}{x}+C_2x^2+x^2logx+\frac{1}{2}$

Hence, general solution G.S= $C_1\frac{1}{x}+C_2x^2+x^2logx+\frac{1}{2}$

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4 years ago