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3 years ago

What does the left side of the equal sign simplify to?

Mathematics

2 answers:

polet [3.4K]3 years ago

6 0

Answer:

Step-by-step explanation:

An expression is a mathematical statement that does not contain an equal sign. It cannot be solved for unless the value of the variable is given. An equation is a mathematical statement or sentence comprised of two equalities or expressions joined with an equal sign.

Tom [10]3 years ago

3 0

If the left side is equal to the right side your answer is correct.

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Triangle OWL was rotated to create triangle O'W'L'. Describe the transformation using details and degrees.

Alisiya [41]

I believe this is a rotation through an angle of +90°, anticlockwise, (counterclockwise), with the center of rotation origin(0,0)
To describe rotation we give the center of rotation and the rotation angle in degrees stating whether it is clockwise or counterclockwise.

8 0

3 years ago

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Question 4 (1 point)

igomit [66]

Answer:

x = 15

Step-by-step explanation:

We want to solve for x in 3*(2x + 5) = 3x + 4x

First simplify.

3*(2x + 5) = 7x

Next, distribute the 3.

3*2x + 3*5 = 7x

6x + 15 = 7x

15 = 7x - 6x

15 = x

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2 years ago

What is the slope of the line that passes through the points (-3,1) and (7,-14)

Katyanochek1 [597]

Answer:

$- \frac{3}{2}$

Step-by-step explanation:

$\boxed{gradient = \frac{y1 - y2}{x1 - x2} }$

Using the formula above,

slope of line

$= \frac{1 - ( - 14)}{ - 3 - 7} \\ = \frac{1 + 14}{ - 10} \\ = \frac{15}{ - 10} \\ = - \frac{3}{2}$

5 0

3 years ago

What is the slope of the line x+3y=10

Minchanka [31]

Answer:

m = -1/3

Step-by-step explanation:

Slope-Intercept Form: y = mx + b

Step 1: Write equation

x + 3y = 10

Step 2: Convert to slope-intercept form

3y = 10 - x

y = 10/3 - x/3

We see that our slope would be the term -1/3x. Since m is the coefficient of x and our slope, our slope m = -1/3

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3 years ago

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Find the area of the triangle 1. C=110 degrees, a=6, b=10 2. B=130 degrees, a=92, c=30

wel

$1.\ \ \ |\angle \ ACB|=110^0\\\\.\ \ \ \ \ a=|BC|=6\ [u]\ \ \ and\ \ \ b=|AC|=10\ [u]\\\\Area= \frac{1}{2} \cdot |AC|\cdot |BC|\cdot sin(|\angle \ ACB|)\\\\Area= \frac{1}{2} \cdot 6\cdot 10\cdot sin110^0=30\cdot sin (180^0-70^0)=\\\\.\ \ \ \ \ \ =30\cdot sin70^0\approx30\cdot 0.9397=28.191\ [u^2]\\\\$

$2.\ \ \ |\angle \ ABC|=130^0\\\\.\ \ \ \ \ a=|BC|=92\ [u]\ \ \ and\ \ \ c=|AB|=30\ [u]\\\\Area= \frac{1}{2} \cdot |AB|\cdot |BC|\cdot sin(|\angle \ ABC|)\\\\Area= \frac{1}{2} \cdot 30\cdot 92\cdot sin130^0=1380\cdot sin (180^0-50^0)=\\\\.\ \ \ \ \ \ =1380\cdot sin50^0\approx1380\cdot 0.7660=1057.08\ [u^2]\\\\$

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3 years ago