Answer:
A solution to a linear equation means that the ordered pair is a point that lies on that line.
If someone were to say (2,5) is a solution to the equation y= 2x+3, you could check them by plugging in 2 where the variable "x" and seeing if y =5.
In this case,
y= 2(2)+3
y=7
(2,5) is not a solution.
Answer:
RTA= (x-2)·(x-11/2)/(x-2)(x-4)= (you can simplify again if you want by eliminating both (x-2)
(x-11/2)/(x-4)
Step-by-step explanation:
Ok we need to simplify the expression so:
x^2+3x-10= Bhaskara formula=
-3(±√9-4·1·(-10))/2·1=
X1=(-3+7/2)--> X1=2(R)---> (X-R)--->X-2
X2=(-3-7)/2 --> X2=11/2(R)---> (X-R)--->X-11/2
x^2-6x+8= Bhaskara formula=
6(±√36-4·1·8)/2·1=
X1=(6-2)/2=2--> X1=2(R)---> (X-R)--->X-2
X2=(6+2)/2=2--> X2=4(R)---> (X-R)--->X-4
so, The simplify expression is
(x-2)·(x-11/2)/(x-2)(x-4)=
Answer:
450
Step-by-step explanation:
find perimeter of bases and then the area. then find Lateral Surface area to get Surface area
Answer: 2654
Step-by-step explanation:
you take jolly's number 4599 and subtract Gopal's number of 1945
Time wind time speed divide by 3
