HELP ME *** if you give the wrong answer you will be reported

Help me on this pleasseeee

EastWind [94]

Answer:

1) E and F

Step-by-step explanation:

So width is x

legth Is 3x+3

Perimeter is

3x+3+3x+3+x+x

Now simplify

8x+6

Now go through each choice that equals 8x+6

Only e and f

8 0

2 years ago

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563 pints equals how many cups <br><br> Answer:

Firdavs [7]

Answer:

1126 cups

Step-by-step explanation:

hope this helps :3

if it did pls mark brainliest

4 0

3 years ago

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In the circle below tangent PA and secant PBC have been drawn.if PB=4 and BC=12 then which of the following is the length of tan

Vinvika [58]

The length of the tangent PA is gonna be 8

5 0

3 years ago

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Write the polynomial f(x)=x^4-10x^3+25x^2-40x+84. In factored form

Verizon [17]

<h2>Steps:</h2>

So firstly, to factor this we need to first find the potential roots of this polynomial. To find it, the equation is $\pm \frac{p}{q}$ , with p = the factors of the constant and q = the factors of the leading coefficient. In this case:

$\textsf{leading coefficient = 1, constant = 84}\\\\p=1,2,3,4,6,7,12,14,21,28,42,84\\q=1\\\\\pm \frac{1,2,3,4,6,7,12,14,21,28,42,84}{1}\\\\\textsf{Potential roots =}\pm 1, \pm 2,\pm 3,\pm 4,\pm 6, \pm 7,\pm 12,\pm 14,\pm 21,\pm 28,\pm 42,\pm 84$

Next, plug in the potential roots into x of the equation until one of them ends with a result of 0:

$f(1)=(1)^4-10(1)^3+25(1)^2-40(1)+84\\f(1)=1-10+25-40+84\\f(1)=60\ \textsf{Not a root}\\\\f(2)=2^4-10(2)^3+25(2)^2-40(2)+84\\f(2)=16-10*8+25*4-80+84\\f(2)=16-80+100-80+84\\f(2)=80\ \textsf{Not a root}\\\\f(3)=3^4-10(3)^3+25(3)^2-40(3)+84\\f(3)=81-10*27+25*9-120+84\\f(3)=81-270+225-120+84\\f(3)=0\ \textsf{Is a root}$

Since we know that 3 is a root, this means that one of the factors is (x - 3). Now that we know one of the roots, we are going to use synthetic division to divide the polynomial. To set it up, place the root of the divisor, in this case 3 from x - 3, on the left side and the coefficients of the original polynomial on the right side as such:

3 | 1 - 10 + 25 - 40 + 84
_________________

Firstly, drop the 1:

3 | 1 - 10 + 25 - 40 + 84
↓
_________________
1

Next, multiply 3 and 1, then add the product with -10:

3 | 1 - 10 + 25 - 40 + 84
↓ + 3
_________________
1 - 7

Next, multiply 3 and -7, then add the product with 25:

3 | 1 - 10 + 25 - 40 + 84
↓ + 3 - 21
_________________
1 - 7 + 4

Next, multiply 3 and 4, then add the product with -40:

3 | 1 - 10 + 25 - 40 + 84
↓ + 3 - 21 + 12
_________________
1 - 7 + 4 - 28

Lastly, multiply -28 and 3, then add the product with 84:

3 | 1 - 10 + 25 - 40 + 84
↓ + 3 - 21 + 12 - 84
_________________
1 - 7 + 4 - 28 + 0

Now our synthetic division is complete. Now since the degree of the original polynomial is 4, this means our quotient has a degree of 3 and follows the format $ax^3+bx^2+cx+d$ . In this case, our quotient is $x^3-7x^2+4x-28$ .

So right now, our equation looks like this:

$f(x)=(x-3)(x^3-7x^2+4x-28)$

However, our second factor can be further simplified. For the second factor, I will be factoring by grouping. So factor x³ - 7x² and 4x - 28 separately. Make sure that they have the same quantity inside the parentheses:

$f(x)=(x-3)(x^2(x-7)+4(x-7))$

Now it can be rewritten as:

$f(x)=(x-3)(x^2+4)(x-7)$

<h2>Answer:</h2>

Since the polynomial cannot be further simplified, your answer is:

$f(x)=(x-3)(x^2+4)(x-7)$

6 0

3 years ago

One vertex of a triangle is located at (0, 5) on a coordinate grid. After a transformation, the vertex is located at (5, 0). Whi

madreJ [45]

Answer:

The Transformations are R(O , -90°) & R(O , 270)

Step-by-step explanation:

* Lets revise the rotation of a point

- If point (x , y) rotated about the origin by angle 90° anti-clock wise

∴ Its image is (-y , x)

- If point (x , y) rotated about the origin by angle 90° clock wise

(270° anti-clockwise or -90°)

∴ Its image is (y , -x)

- If point (x , y) rotated about the origin by angle 180°

∴ Its image is (-x , -y)

* There is no difference between rotating 180° clockwise (-180°) or

anti-clockwise (180°) around the origin

* Lets solve the problem

∵ One vertex of a triangle is located at (0, 5) on a coordinate grid

∵ The image of the point after the transformation is (5 , 0)

- The coordinates are switched with each other

∴ There is no rotation with 180° or -180° because in the rotation with

180° and -180° around the origin we change only the signs of the

coordinates without switch them

∴ There is a rotation with 90° are 270° or -90°

- The zero has no sign

- When we rotate the point (0 , 5) by -90° or 270° around the origin

we will change the sign of x-coordinate and switch the two

coordinates

∴ The image of the point is (y , -x)

∵ x = 0 and y = 5

- There is no sign for zero, so we switch the coordinates only

∴ The vertex is located at (5, 0)

∴ The Transformations are R(O , -90°) & R(O , 270)

3 0

3 years ago

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