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Brilliant_brown [7]

3 years ago

7

A half cup of grapes contains 56 calories. This is twice the number of calories in a half cup of watermelon. How many calories a

re in a cup of watermelon?

2 answers:

siniylev [52]3 years ago

3 0

Answer:

28

Step-by-step explanation:

56/2=28

vovangra [49]3 years ago

3 0

<em>Answer:</em>

<em>The answer would be 28</em>

<em>Step-by-step explanation:</em>

<em>The answer would be </em><u><em>28 because 56/2 = 28</em></u>

<em></em>

<em>Hope this helps</em>

<em></em>

<em>Please give me Brainliest</em>

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Wich is an equetion of the line that passes through the points (4,2) and (0,-1)

antiseptic1488 [7]

Answer:

y

=

2

x

−

1

Explanation:

First, we need to determine the slope of the line. The formula for determining the slope of a line is:

m

=

y

2

−

y

1

x

2

−

x

1

where

m

is the slope and the x and y terms are for the points:

(

x

1

,

y

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)

and

(

x

2

,

y

2

)

For this problem the slope is:

m

=

3

−

−

1

2

−

0

m

=

3

+

1

2

m

=

4

2

m

=

2

Now, selecting one of the points we can use the point slope formula to find the equation.

The point slope formula is:

y

−

y

1

=

m

(

x

−

x

1

)

Substituting one of our points gives:

y

−

−

1

=

2

(

x

−

0

)

y

+

1

=

2

x

Solving for

y

to put this in standard form gives:

y

+

1

−

1

=

2

x

−

1

y

+

0

=

2

x

−

1

y

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2

x

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2 years ago

SOMEONE PLZZZ HELP, I WILL GIVE BRAINLIEST

Soloha48 [4]

Answer:

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Step-by-step explanation:

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3 years ago

The diagram shows a rectangle PQRS.

Aloiza [94]

Answer:

a) The area of the triangle AQB is 43 square centimeters.

b) The length of the line segment AQ is approximately 14.866 centimeters.

Step-by-step explanation:

a) The procedure consist in subtracting the areas of triangles APQ, ASB and BRQ of the area the rectangle, that is to say:

$A = (9\,cm)\cdot (14\,cm) - \frac{1}{2}\cdot (5\,cm)\cdot (14\,cm) - \frac{1}{2}\cdot (8\,cm)\cdot (9\,cm) -\frac{1}{2}\cdot (4\,cm) \cdot (6\,cm)$

$A = 43\,cm^{2}$

The area of the triangle AQB is 43 square centimeters.

b) The length of the line segment AQ is determined by Pythagorean Theorem:

$AQ = \sqrt{AP^{2}+PQ^{2}}$ (1)

$AQ = \sqrt{(5\,cm)^{2}+(14\,cm)^{2}}$

$AQ \approx 14.866\,cm$

The length of the line segment AQ is approximately 14.866 centimeters.

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vazorg [7]

Use inverse to solve this problem. Cos-1(2/5)=66.421=66.

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